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Mila [183]
3 years ago
15

If m = 2, n = 3 and p = 0; then what is the value of 4mp + 3n​

Mathematics
2 answers:
Brut [27]3 years ago
7 0

Answer:

9

Step-by-step explanation:

4mp + 3n

Given:

m = 2

n = 3

p = 0

Work:

4mp + 3n

4(2)(0) + 3(3)

0 + 9

9

MAXImum [283]3 years ago
6 0

Answer: The answer is 9.

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ALGEBRA 2!!!!!!!HELP
Inessa [10]

Answer:

x = - 1, x = - 11

Step-by-step explanation:

Given

2| x + 6 | - 4 = 6 ( add 4 to both sides )

2|x + 6 | = 10 ( divide both sides by 2 )

| x + 6 | = 5

The absolute value function always gives a positive result, but the expression inside can be positive or negative, that is

x + 6 = 5 or - (x + 6) = 5

solve both

x + 6 = 5 ( subtract 6 from both sides )

x = - 1

or

- (x + 6) = 5 , that is

- x - 6 = 5 ( add 6 to both sides )

- x = 11 ( multiply both sides by - 1 )

x = - 11

8 0
2 years ago
3+-1/1/3 the first half is 3+-1 the second half is 1/3
kolbaska11 [484]
\bf \cfrac{3\pm1}{\frac{1}{3}}\implies 
\begin{cases}
\cfrac{3+1}{\frac{1}{3}}\\\\
\cfrac{3-1}{\frac{1}{3}}
\end{cases}\\\\
-------------------------------\\\\

\bf \cfrac{3+1}{\frac{1}{3}}\implies \cfrac{4}{\frac{1}{3}}\implies \cfrac{\frac{4}{1}}{\frac{1}{3}}\implies \cfrac{4}{1}\cdot \cfrac{3}{1}\implies \cfrac{4\cdot 3}{1\cdot 1}\implies \cfrac{12}{1}\implies \boxed{12}
\\\\\\
\cfrac{3-1}{\frac{1}{3}}\implies \cfrac{2}{\frac{1}{3}}\implies \cfrac{\frac{2}{1}}{\frac{1}{3}}\implies \cfrac{2}{1}\cdot \cfrac{3}{1}\implies \cfrac{2\cdot 3}{1\cdot 1}\implies \cfrac{6}{1}\implies \boxed{6}
6 0
3 years ago
What is the sum of the first 70 consecutive odd numbers? Explain.
expeople1 [14]

The sum of the first n odd numbers is n squared! So, the short answer is that the sum of the first 70 odd numbers is 70 squared, i.e. 4900.

Allow me to prove the result: odd numbers come in the form 2n-1, because 2n is always even, and the number immediately before an even number is always odd.

So, if we sum the first N odd numbers, we have

\displaystyle \sum_{i=1}^N 2i-1 = 2\sum_{i=1}^N i - \sum_{i=1}^N 1

The first sum is the sum of all integers from 1 to N, which is N(N+1)/2. We want twice this sum, so we have

\displaystyle 2\sum_{i=1}^N i = 2\cdot\dfrac{N(N+1)}{2}=N(N+1)

The second sum is simply the sum of N ones:

\underbrace{1+1+1\ldots+1}_{N\text{ times}}=N

So, the final result is

\displaystyle \sum_{i=1}^N 2i-1 = 2\sum_{i=1}^N i - \sum_{i=1}^N 1 = N(N+1)-N = N^2+N-N = N^2

which ends the proof.

5 0
2 years ago
Find the area D (1,3) F (-4,-3) E (4, -3)​
tresset_1 [31]

Answer:

Step-by-step explanation:

FE=4+4=8

Altitude=3+3=6

area=1/2×FE×6=1/2×8×6=24 sq. units.

or

area=1/2×

I 1   3|

|-4 -3|

| 4 -3|

|  1  3|

=1/2[(-3+12)+(12+12)+(12+3)]

=1/2[9+24+15]

=1/2[48]

=24 sq. units

7 0
2 years ago
Can someone please explain 7 and 8 to me? I really don’t get it that well. On 7, why are they congruent? Why is it false for 8?
Crazy boy [7]

Answer: Look below :)

Step-by-step explanation:

7. <u>AD</u> and <u>CD</u> are congruent.  Each of the triangles are the same in length and shape (both are right triangles). They are the same but are mirrored over the line <u>BD.</u>

8.  I have no idea. Sorry.

5 0
3 years ago
Read 2 more answers
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