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Finger [1]
2 years ago
8

How do you find surface area of a rectangular prism

Mathematics
1 answer:
garri49 [273]2 years ago
8 0

Answer:

To find the surface area of a rectangular prism, measure the length, width, and height of the prism. Find the area of the top and bottom faces by multiplying the length and width of the prism. Then, calculate the area of the left and right faces by multiplying the width and height.

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What is the answer for this equation or problem? y+6=52 and what does y equal.
Cloud [144]

Answer: y=46

Step-by-step explanation:

Subtract 6 from either side to ensure that the y is alone. This then equals y=52-6.

52-6= 46

So therefore, y=46

4 0
3 years ago
Read 2 more answers
What is the equation of the line passing through the points (Two-fifths, StartFraction 19 Over 20 EndFraction) and (one-third, S
Elan Coil [88]

Answer:

You have to find the slope first. Which is y1-y1 divided by x1-x2

Then you find the y-intercept which you take the slope for m like for example if you find the slope, 2, then the equation should be y=2x+b. You take the coordinates on the problem and put them on the y or x on the equation. Then when you find the y-intercept you add it to the equation like for the example that I used above, you have to put the y-intercept on b. So if the y-intercept is 5 then the equation would be y=2x+5.

5 0
3 years ago
I arrive at a bus stop at a time that is normally distributed with mean 08:00 and SD 2 minutes. My bus arrives at the stop at an
Nimfa-mama [501]

Answer:

0.0485 = 4.85% probability that you miss the bus.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When two normal distributions are subtracted, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

In this question:

We have to find the distribution for the difference in times between when you arrive and when the bus arrives.

You arrive at 8, so we consider the mean 0. The bus arrives at 8:05, 5 minutes later, so we consider mean 5. This means that the mean is:

\mu = 0 - 5 = -5

The standard deviation of your arrival time is of 2 minutes, while for the bus it is 3. So

\sigma = \sqrt{2^2 + 3^2} = \sqrt{13}

The bus remains at the stop for 1 minute and then leaves. What is the chance that I miss the bus?

You will miss the bus if the difference is larger than 1. So this probability is 1 subtracted by the pvalue of Z when X = 1.

Z = \frac{X - \mu}{\sigma}

Z = \frac{1 - (-5)}{\sqrt{13}}

Z = \frac{6}{\sqrt{13}}

Z = 1.66

Z = 1.66 has a pvalue of 0.9515

1 - 0.9515 = 0.0485

0.0485 = 4.85% probability that you miss the bus.

5 0
3 years ago
Somebody help me please i will mark you the brainliest
Reptile [31]
I’m 100% sure it’s the 3rd one :)
5 0
3 years ago
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I need this done by today someone plzz help me !!!
Pie
(is/of=%/100)
(12/x= 35/100) = 34.29
(500/400=x/100) = 125
8 0
3 years ago
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