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charle [14.2K]
3 years ago
15

Write y = 3x2-12x +11 in vertex form. please show work

Mathematics
2 answers:
MaRussiya [10]3 years ago
6 0

Answer:

y = 3 ( x − 2 ) 2 − 1

Step-by-step explanation:

To convert a quadratic from y = ax2 + bx + c form to vertex form, y = a(x - h)2+ k, you use the process of completing the square. Let's see an example. Convert y = 2x2 - 4x + 5 into vertex form, and state the vertex. Equation in y = ax2 + bx + c form.

Very glad I was able to assist you even though you're pretty rude.

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Studentka2010 [4]3 years ago
4 0
Ohhh ok so im actually not sure if I’m doing this right but if I remember correctly.. there has to be a squared binomial so heres my answer:

3(x-2)^2-1 and the vertex is (2,-1)

Now im not completely sure if I’m right but basically what I did was get a squared binomial and added and multiplied to it to make it equal to the previous trinomial.

Sorry if I’m wrong. Hope this helps some.
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What is the answer to 9×(6+7-3)-2​
ZanzabumX [31]

Answer:

88

Step-by-step explanation:

PEMDAS

9*(6+7-3)-2

1) 6+7=13

13-3=10

9*10-2

2)9*10= 90

3)90-2= 88

3 0
3 years ago
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What is 5.6 equalivent to
Sloan [31]
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3 years ago
Can someone explain how to due this
ElenaW [278]
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7 0
3 years ago
Mr. Cooper is making homework packets. He will put 6 worksheets in each packet. There are 18 worksheets. How many packets can he
ziro4ka [17]

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8 0
3 years ago
The first term of a geometric sequence is 32, and the 5th term of the sequence is 818 .
sammy [17]

Answer:

32,24,18,\frac{27}{2} ,\frac{81}{8}

Step-by-step explanation:

Let x, y , and z be the numbers.

Then the geometric sequence is 32,x,y,z,\frac{81}{8}

Recall that  term of a geometric sequence  are generally in the form:

a,ar,ar^2,ar^3,ar^4

This implies that:

a=32 and ar^4=\frac{81}{8}

Substitute a=32 and solve for r.

32r^3=\frac{81}{8}

r^4=\frac{81}{256}

Take the fourth root to get:

r=\sqrt[4]{\frac{81}{256} }

r=\frac{3}{4}

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z=18*\frac{3}{4} =\frac{27}{2}

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