The required point-slope form of the equation of the line is y - 5 = -4(x + 1).
Given that, To determine an equation in point-slope form for the line that passes through the point with the given slope. point: (-1, 5) and m=-4.
What is the slope of the line?
The slope of the line is a tangent angle made by line with horizontal. i.e. m =tanx where x in degrees.
Here,
The point-slope of the equation of the line is given by,
y - y₁ = m(x - x₁)
Put the values in the above equation of the line
y - 5 = -4 (x - (-1))
y - 5 = -4 (x + 1)
Thus, the required point-slope form of the equation of the line is y - 5 = -4(x + 1).
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Step-by-step explanation:
Since line NL is not necessarily congruent to MQ (labelled with different congruent marks), triangle NLM is not congruent to triangle MQP.
Instead, triangles NLM and QPM are congruent.
Do 4.98*7 5/8 and then you will have your answer its all in the question
It’s - ( - 3 ) because a negative times a negative equals a positive so it wouldn’t be - ( 3 ) because it would turn into a negative number and - ( - 3 ) would be positive
