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3 years ago

12

Mateo went out to eat dinner, and the meal cost $30.00. If Mateo received a 12% discount, what was the total value of the discou

nt?
Please help im dumb

1 answer:

Vanyuwa [196]3 years ago

4 0

Answer:

3.6

Step-by-step explanation:

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I report if you answer randomly. Don't steal my points, go steal someone elses.

Sav [38]

Answer:

D

Step-by-step explanation:

p +/- [z + sqrt(pq/n)]

0.65 + [1.645 × sqrt[0.65 × (1-0.65) ÷ 50]

0.65 +/- 0 1109613165

[0.5390386835 , 0.7609613165]

6 0

3 years ago

3x + 2 y = 8<br> 5x + 2 y = 12<br> What is the solution of the system of equations shown above?

Arisa [49]

Answer:

x = -3

Step-by-step explanation:

First solve it:

Subtract the x's from both sides

2y = -3x +8

2y = -5x +2

Divide by two

y= -1.5x + 4

y = -2.5x +1

set them equal to each other:

-1.5x +4 = -2.5x +1

Add 2.5 x to both sides

1x +4 = 1

x +4 = 1

subtract 4 from both sides

x = -3

5 0

2 years ago

The manager wants to advertise that anybody who isn't served within a certain number of minutes gets a free hamburger. But she d

aksik [14]

Answer:

The number of minutes advertisement should use is found.

x ≅ 12 mins

Step-by-step explanation:

(MISSING PART OF THE QUESTION: AVERAGE WAITING TIME = 2.5 MINUTES)

<h3 /><h3>Step 1</h3>

For such problems, we can use probability density function, in which probability is found out by taking integral of a function across an interval.

Probability Density Function is given by:

$f(t)=\left \{ {{0 ,\-t$

Consider the second function:

$f(t)=\frac{e^{-t/\mu}}{\mu}\\$

Where Average waiting time = μ = 2.5

The function f(t) becomes

$f(t)=0.4e^{-0.4t}$

<h3>Step 2</h3>

The manager wants to give free hamburgers to only 1% of her costumers, which means that probability of a costumer getting a free hamburger is 0.01

The probability that a costumer has to wait for more than x minutes is:

$\int\limits^\infty_x {f(t)} \, dt= \int\limits^\infty_x {}0.4e^{-0.4t}dt$

which is equal to 0.01

<h3>Step 3</h3>

Solve the equation for x

$\int\limits^{\infty}_x {0.4e^{-0.4t}} \, dt =0.01\\\\\frac{0.4e^{-0.4t}}{-0.4}=0.01\\\\-e^{-0.4t} |^\infty_x =0.01\\\\e^{-0.4x}=0.01$

Take natural log on both sides

$ln (e^{-0.4x})=ln(0.01)\\-0.4x=ln(0.01)\\-0.4x=-4.61\\x= 11.53$

<h3>Results</h3>

The costumer has to wait x = 11.53 mins ≅ 12 mins to get a free hamburger

3 0

3 years ago

Question 5^ Need help ... ASAP ... your help is really appreciated ...

goblinko [34]

Answer:

See below

Step-by-step explanation:

I think we had a question similar to this before. Again, let's figure out the vertical and horizontal distances figured out. The distance from C at x=8 to D at x=-5 is 13 units while the distance from C at y=-2 to D at y=9 is 11 units. (8+5=13 and 2+9=11, even though some numbers are negative, we're looking at their value in those calculations)

Next, we have to divide each distance by 4 so we can apply it to the ratio. 13/4= $\frac{13}{4}$ and 11/4= $\frac{11}{4}$ . Next, we need to read the question carefully. It's asking us to place the point in the ratio <em>3</em> to <em>1</em> from <em>C</em> to <em>D</em>. The point has to be closer to endpoint D because of this. Let's take each of our fractions, multiply them by 3, then add them towards the direction of endpoint D to get our answer (sorry if that sounds confusing):

$\frac{13}{4}*3 = \frac{39}{4}\\ 8-\frac{39}{4} = \frac{-7}{4}\\\frac{11}{4}*3 = \frac{33}{4} \\-2+\frac{33}{4} = \frac{25}{4}$

Therefore, our point that partitions CD into a 3:1 ratio is ( $\frac{-7}{4}, \frac{25}{4}$ ).

I'm not sure if there was more to #5 judging by how part B was cut off. From what I can understand of part B, however, I believe that Beatriz started from endpoint D and moved towards C, the wrong direction. She found the coordinates for a 1:3 ratio point.

Also, for #6, since a square is a 2-dimensional object, the answer needs to be written showing that. The answer for #6 is 9 units^2.

7 0

3 years ago

g100num [7]

Answer:

the answer is 7/12 hours

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers