If the two diagonals are 
and 
, the are of the rhombus is
So, in your case, the area is
The other options are wrong because:
- option A doens't divide by 2, thus getting twice the area of the rhombus
- option B summed the diagonals instead of multiplying them
- option D took the difference of the diagonals.
Answer:
steps below
Step-by-step explanation:
7, 11, 15, 19 ...
common difference (d) = 11-7 = 4
Recursive rule: A(n) = A(n-1) + d = A(n-1) + 4
Explicit rule: A(n) = A(1) + d * (n-1) = A(1) + 4 *(n-1) = 7 + 4 * (n-1) = 4n + 3
15th term: A(15) = 4 * 15 + 3 = 63
Answer:
56/65
Step-by-step explanation:
First, we know that cos(a-b) = cos(a)cos(b) + sin(a)sin(b)
We know what sin(a) and sin(b) are, and to get cos(a), we can take the equation sin²a + cos²a = 1
Thus,
(12/13)² + cos²a = 1
1 - (12/13)² = cos²a
1- 144/169 = cos²a
cos²a = 25/169
cos(a) = 5/13
Similarly,
(3/5)² + cos²b = 1
1 - (3/5)² = cos²b
1 - 9/25 = cos²b
cos²b = 16/25
cos(b) = 4/5
Our answer is
cos(a-b) = cos(a)cos(b) + sin(a)sin(b)
cos(a-b) = (5/13)(4/5) + (12/13)(3/5)
cos(a-b) = 20/65 + 36/65
cos(a-b) = 56/65
Answer:
700
Step-by-step explanation:
539 rounded to 500
221 rounded to 200
500 plus 200 is 700
