Answer:
1
Step-by-step explanation:
Using the trigonometric identities
tan(90 - x) = cotx , cotx = ![\frac{1}{tanx}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Btanx%7D)
Given
tan1tan2tan3....................... tan87tan88tan89
= tan1tan2tan3............... tan(90-3)tan(90-2)(tan90 - 1)
= tan1tan2tan3.............. cot3cot2cot1
= tan1cot1tan2cot2tan3cot3 ........................
= 1 × 1 × 1 ×....................... × 1
= 1
Answer:
12/13
Step-by-step explanation:
Given that MN = 5, NO = 12, and MO = 13, find cos O.
Since the reference angle is P, hence;
MN is the opposite = 5
MO is the hypotenuse = 13 (longest side)
NO is the adjacent = 12
Cos O = adj/hyp
Substitute the given values
Cos O = 12/13
Hence the value of Cos O is 12/13
3/4 = .75 so you have to find 75 % of 3/9
100% = 3/9
1% = (3/9)/100
75% = (3/9)/100 * 75 =.25
all of them except the last efg and bcd
Answer:
B
Step-by-step explanation:
using the equation 'y = 12x', if you plug in zero for 'x' you get zero for 'y'; the only graph that has the point (0, 0) is (b)
also, the x-axis represents time so, as time increases, so does the number of calories burned (which is measured on the y-axis) -- not staying flat or decreasing