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liberstina [14]
3 years ago
7

Need some help, please. :)

Mathematics
1 answer:
Elden [556K]3 years ago
6 0

Answer:

C

Step-by-step explanation:

Trust me on this ;V

I have the same problem,

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X+x+x+y+y<br><br> Simply the following
laila [671]

Ắner 3x+2y

Step-by-step explanation:

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Find the inverse function of <br> (Show work)<br><br> f(x)=x^2-4
Olegator [25]

Answer:

The answer to your question is f(x) = \sqrt{x+ 4}

Step-by-step explanation:

                                           f(x) = x² - 4

Process

1.- Change f(x) for y

                                           y = x² - 4

2.- Change "x" for "y" and "y" for "x".

                                           x = y² - 4

3.- Make "y" the object of the equation

                                          y² = x + 4

                                          y = \sqrt{x+ 4}

4.- Change "y" for f(x)

                                          f(x) = \sqrt{x+ 4}

4 0
3 years ago
What's 1394 divided by 36
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The answer would be 38.722222 (the two just keeps repeating)
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Consider the following argument. If I get a Christmas bonus, I'll buy a stereo. If I sell my motorcycle, I'll buy a stereo. ∴ If
Nuetrik [128]

Answer:

p → r valid, proof by division into cases

q → r

∴ p ∨ q → r

Step-by-step explanation:

Let

p = "if I get a Christmas bonus,"

q = "if I sell my motorcycle,"

and

r = "I'll buy a stereo."

This can be written as:

If I get a Christmas bonus, I'll buy a stereo

p → r

If I sell my motorcycle, I'll buy a stereo

q → r

∴ If I get a Christmas bonus or I sell my motorcycle, then I'll buy a stereo.

∴ p ∨ q → r

To prove this argument we partition the argument into a group of smaller statements that together cover all of the original argument and then we prove each of the smaller statements. If you see the conclusion ∴ p ∨ q -> r so if the conclusion contains a conditional argument of form "If A1  or A2 or... or An then C ”, then we prove "If A1 then C", "If A2 then C" and so on upto "If An then C" . This depicts that the conclusion  C is true no matter which if the Ai holds true. This method is called proof by division into cases. In the given example, this takes the form:

p → r

q → r

p ∨ q

∴ r

Since proof by division into cases is an inference rule thus given argument is valid. Lets make a truth table to show if this argument is valid

p   q   r   p ∨ q   p → r    q → r    p ∨ q → r

0   0   0     0        1           1             1

0   0   1      0        0          0            0

0   1    0     1         1           0            0

0   1    1      1         0          1               1

1    0   0     1         0          1             0    

1    0   1      1         1           0            1    

1    1    0     1         0          0            0    

1    1    1      1         1           1              1    

An argument is valid if all of the premises are true, then the conclusion is true. So the truth table shows that the conclusion is true i.e. 1 where all premises are true i.e. 1. So the argument is valid.

Hence

p → r valid, proof by division into cases

q → r

∴ p ∨ q → r

4 0
3 years ago
Gary needs 24 screws for every 2 chairs he builds
kicyunya [14]

Answer:

ok sooo is there something you need to be figured out orr are you just saying

Step-by-step explanation:

7 0
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