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2 years ago

What is the fifteenth term of the sequence

Mathematics

1 answer:

eduard2 years ago

6 0

Answer:

81920.

Step-by-step explanation:

1) the ration of the given sequence is -2=-10/5=20/(-10)...

2) the 15th term can be calculated according to the formula:

a₁₅=a₁*(ratio)¹⁴, then

a₁₅=5*(-2)¹⁴=-5*1024*16=81920.

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Here are two sets of numbers, a and b. Set a :200,104,100,160. Set b: 270,400,483,300, x. Mean of set a: mean of set b= 3:8. Wor

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Given:

The given sets are:

Set a : 200, 104, 100, 160.

Set b: 270, 400, 483, 300, x.

Mean of set a: mean of set b= 3:8

To find:

The value of x.

Solution:

Formula for mean:

$Mean=\dfrac{\text{Sum of observations}}{\text{Number of observation}}$

The mean of set of a is:

$Mean=\dfrac{200+104+100+160}{4}$

$Mean=\dfrac{564}{4}$

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$Mean=\dfrac{270+400+483+300+x}{5}$

$Mean=\dfrac{1453+x}{5}$

It is given that,

Mean of set a: mean of set b= 3:8

$\dfrac{141}{\dfrac{1453+x}{5}}=\dfrac{3}{8}$

$\dfrac{705}{1453+x}=\dfrac{3}{8}$

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Isolate the variable x.

$5640-4359
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Divide both sides by 3.

$\dfrac{1281}{3}
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Therefore, the value of x is 427.

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2 years ago