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inysia [295]
1 year ago
13

There are 28 students in a class. Two of the students are named Emily. What is the approximate probability that either Emily is

chosen at random?
Mathematics
1 answer:
anyanavicka [17]1 year ago
5 0

Answer:

answer is 7

Step-by-step explanation:

they are saying 28 students that means we have to divide the name because their are two students name Emily

28/2= 14 then

14/2=7

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C/ 8= 9. What does c equal
Norma-Jean [14]

Answer: 72

72/8 will get you 9. To see if the answer is correct Multiply 9*8.

7 0
2 years ago
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three sets of the sum of a number and four are added to the sum of seven times the same number and thirteen
almond37 [142]

The algebraic expression for given statement is: 10x + 25 or 3(x + 4) + (7x + 13)

<em><u>Solution:</u></em>

Given the statement:

Three sets of a sum of a number and four are added to the sum of seven times the same number and thirteen

Let us first understand the given statement,

Let the number be "x"

" sum of a number and four" means x + 4

"Three sets of a sum of a number and four" translated to 3(x + 4)

"sum of seven times the same number and thirteen" means 7x + 13

<em><u>Thus the algebraic expression for given statement is:</u></em>

3(x+4)+(7x + 13)

<em><u>Using distributive property in above expression</u></em>

a(b+c) = ab + bc

Therefore,

3(x+4)+(7x + 13) = 3x + 12 + 7x + 13

<em><u>Combine the like terms</u></em>

3(x+4)+(7x + 13) = 10x+25

Thus the required expression for given statement is: 10x + 25 or 3(x + 4) + (7x + 13)

7 0
2 years ago
Riley started selling bracelets. During the first month she sold 400 bracelets at $10 each. She tried raising the price, but for
love history [14]
I would just divide 400 and 10 and then try to come up with the salary
8 0
3 years ago
Simplify the expression below, I really just need the steps I have the answer (also can someone tell me how to edit points on th
Sloan [31]

Answer:  3x^2y\sqrt[3]{y}\\\\

Work Shown:

\sqrt[3]{27x^{6}y^{4}}\\\\\sqrt[3]{3^3x^{3+3}y^{3+1}}\\\\\sqrt[3]{3^3x^{3}*x^{3}*y^{3}*y^{1}}\\\\\sqrt[3]{3^3x^{2*3}*y^{3}*y}\\\\\sqrt[3]{\left(3x^2y\right)^3*y}\\\\\sqrt[3]{\left(3x^2y\right)^3}*\sqrt[3]{y}\\\\3x^2y\sqrt[3]{y}\\\\

Explanation:

As the steps above show, the goal is to factor the expression under the root in terms of pulling out cubed terms. That way when we apply the cube root to them, the exponents cancel. We cannot factor the y term completely, so we have a bit of leftovers.

4 0
2 years ago
Tell whether the ordered pair (- 3, 0) is a solution of the given system. - 2x + 2y &gt;= 4an y &gt;= 2x - 6
alukav5142 [94]

Answer:

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Step-by-step explanation:

Plug x = -3 and y = 0 into the 2 inequalities and see if they fit:

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0 >= 2*-3) - 6 = -12 which also fits.

8 0
2 years ago
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