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Shtirlitz [24]
3 years ago
6

What is the third term of the sequence? a1 = m an = 2an-1 2m 4m 6m 7m

Mathematics
2 answers:
tigry1 [53]3 years ago
5 0

Answer:

a_{3} = 4m).

Step-by-step explanation:

Given  : a_{1} = m and a_{n} = 2 a_{n-1}.

To find : What is the third term of the sequence.

Solution : We have given

a_{1} = m

a_{n} = 2 a_{n-1}.

For  n =2 .

a_{2} = 2 a_{2-1}.

a_{2} = 2 a_{1}.

plug  a_{1} = m

a_{2} = 2m.

For n = 3 .

a_{3} = 2 a_{3-1}.

a_{3} = 2 a_{2}.

Plug a_{2} = 2m.

a_{3} = 2( 2m).

a_{3} = 4m).

Therefore, a_{3} = 4m).

Nady [450]3 years ago
3 0
Rjp912 it should be 4m                       
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Quadrilateral PQRS is a square whos side length is 10. Let X and Y be points outside the square so that XQ = YS = 6 and XP = YR
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392

Step-by-step explanation:

Triangles XQP and YRS are right triangles because triples 6, 8, 10 are Pythagorean triples.

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XY^2=XA^2+AY^2\\ \\XY^2=14^2+14^2\\ \\XY^2=196+196\\ \\XY^2=392  

3 0
3 years ago
Mr. Wells runs a telecommunications company. While going through the company's project records, he found that there were 8 engin
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There are 12 project managers that are employed by Mr. Wells

<h3>Further explanation</h3>

Solving linear equation mean calculating the unknown variable from the equation.

Let the linear equation : y = mx + c

If we draw the above equation on Cartesian Coordinates , it will be a straight line with :

<em>m → gradient of the line</em>

<em>( 0 , c ) → y - intercept</em>

Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :

\large {\boxed{m = \frac{y_2 - y_1}{x_2 - x_1}}}

If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :

\large {\boxed{y - y_1 = m ( x - x_1 )}}

<em>Let us tackle the problem!</em>

\texttt{ }

This problem is about Directly Proportional.

<em>There were 8 engineers under every team leader.</em>

\texttt{1 Team Leader} \rightarrow \texttt{8 engineers}

\texttt{15 Team Leader} \rightarrow 15 \times \texttt{8 engineers} = \boxed{\texttt{120 engineers}}

\texttt{ }

<em>There were 5 project managers for every 50 engineers.</em>

\texttt{50 engineers} \rightarrow \texttt{5 project managers}

\texttt{120 engineers} \rightarrow (120 \div 50) \times \texttt{5 project managers} = \boxed{\texttt{12 project managers}}

\texttt{ }

<h3>Learn more</h3>
  • Infinite Number of Solutions : brainly.com/question/5450548
  • System of Equations : brainly.com/question/1995493
  • System of Linear equations : brainly.com/question/3291576

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

7 0
3 years ago
Help please i really need help
Norma-Jean [14]

The change in the stock market from the beginning of the day to the end of the day is 29 3/4

<h3>How to determine the change in the stock market from the beginning of the day to the end of the day?</h3>

The given parameters are:

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The change in the stock market from the beginning of the day to the end of the day is calculated as;

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So, we have

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Hence, the change in the stock market from the beginning of the day to the end of the day is 29 3/4

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