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Delicious77 [7]
2 years ago
11

• footballs – There are 8 footballs.

Mathematics
1 answer:
inna [77]2 years ago
7 0

Answer:

8 futballs

basketballs 18

beisballs 36

softballs 24

Step-by-step explanation:

dos mas del doble (2) de balones de fut = 8x2 = 16, 16+2 = 18

cuatro menos de 5 veces las pelotas de fut = 8x5 = 40, 40-4 = 36

seis mas de la mitad de beis = 36/2 = 18, 18+6 = 24

LISTO

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Which inequality is true when x = 4?
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x + 5 < 3

Step-by-step explanation:

One inequality could be x > 3. So when x = 4 this is true because 4 is greater than 3.

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Which of the following should you do first when solving the equation 2x-7=3x-2(x+8)
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multiply 3x-2(x+8)

Step-by-step explanation:

PEMDAS

also you must simplify both sides to solve this problem and that's the first step to simplifying this side (the other one is simplified)

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What is the similarity ratio of two squares with areas 75 and 48?
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The answer to this question is 0.64 because you have to divide hope this helps you
 
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3 years ago
Write an expression for the 12th partial sum of the series 3/2+7/3+19/6+... using summation notation
lapo4ka [179]

Answer:

S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]

S_{12}=73

Step-by-step explanation:

First\ term\ of\ the\ series(a_1)=\frac{3}{2}\\\\Second\ term\ of\ the\ series(a_2)=\frac{7}{3}\\\\Third\ term\ of\ the\ series(a_3)=\frac{19}{6}\\\\a_2-a_1=\frac{7}{3}-\frac{3}{2}=\frac{5}{6}\\\\a_3-a_2=\frac{19}{6}-\frac{7}{3}=\frac{5}{6}\\\\Hence\ it\ is\ an\ Arithmetic\ Series\ with\ first\ term=\frac{3}{2}\ and\ constant\ difference=\frac{5}{6}

a_1=\frac{3}{2}+0\times \frac{5}{6}\\\\a_2=\frac{3}{2}+1\times \frac{5}{6}\\\\a_3=\frac{3}{2}+2\times \frac{5}{6}\\\\.\\.\\.\\a_n=\frac{3}{2}+(n-1)\times \frac{5}{6}\\\\S_n=a_1+a_2+a_3+......+a_n\\\\S_n=(\frac{3}{2}+0\times \frac{5}{6})+(\frac{3}{2}+1\times \frac{5}{6})+(\frac{3}{2}+2\times \frac{5}{6})+....+(\frac{3}{2}+[n-1]\times \frac{5}{6})\\\\S_n=\sum_{i=1}^n [\frac{3}{2}+(i-1)\times \frac{5}{6}]\\\\S_n=(\frac{3}{2}+\frac{3}{2}+\frac{3}{2}+...n\ times)+\frac{5}{6}(1+2+3+4+...+(n-1))\\\\

S_n=\frac{3}{2}\times n+\frac{5}{6}\times \frac{n(n-1)}{2}\\\\

S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]

S_{12}=\frac{3}{2}\times 12+\frac{5}{6}\times \frac{(12)(12-1)}{2}\\\\S_{12}=18+55\\\\S_{12}=73

5 0
3 years ago
Need help will def give Brainlyest
Aleksandr-060686 [28]
Your answer will be y=-2/3x+4/3 and I believe I deserve the brainliest answer :))) Hope this helps!

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