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Amanda [17]
3 years ago
13

There are 52 runners in a race. How many ways can the runners finish​ first, second, and​ third?

Mathematics
1 answer:
elena55 [62]3 years ago
5 0

Answer:

126

Step-by-step explanation:

52 * 3 = 126

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Solve for x in the diagram below.<br> 110°<br> (8x +30°
Ulleksa [173]

Answer:

880x+30

880    880

x=29.3 repeating

Step-by-step explanation: Hope this helps

6 0
3 years ago
How can emily use the above to make an estimate for 576 ÷8
Grace [21]

Given the equation :

576\div8​

We will use estimation to find the value of the given expression

So, the best estimation for the number 576 is = 600

The best estimation for the number 8 is = 10

So, the given expression is approximately = 600 ÷ 10 = 60

===================================================================

We can calculate the error of the approximation as following :

The actual value is : 576 ÷ 8 = 72

So, the difference is = 72 - 60 = 12

so, the percentage of error will be :

\frac{12}{72}\cdot100=16.7\%

7 0
1 year ago
Please help me with this
bija089 [108]

Answer: 20 inches

Step-by-step explanation:  You will use the equation 48 x 28 x N = 26,880. To find the solution divide 48 and 28 from 26,880 to get N. To check your work just multiply what you got from N by 48 and 28.

3 0
3 years ago
Please help!! Will give BRAINLIEST!
aniked [119]
D is correct for this problem
4 0
3 years ago
Read 2 more answers
For a certain​ candy, 15​% of the pieces are​ yellow, 1010​% are​ red, 2020​% are​ blue, 55​% are​ green, and the rest are brown
MatroZZZ [7]
A) the probability it is brown would be 50%; the probability it is yellow or blue would be 35%; the probability it is not green is 95%; the probability it is striped is 0%.
B) the probability of all brown would be 12.5%; the probability that the third one is the first red one drawn is 8.1%; the probability that none are yellow is 61.4%; the probability that at least one is green is 14.3%.

Explanation:
A) The probability that it is brown is the percentage of brown we have.  Brown is not listed, so we subtract what we are given from 100%:
100-(15+10+20+5) = 100-(50) = 50%.  The probability that one drawn is yellow or blue would be the two percentages added together:  15+20 = 35%.  The probability that it is not green would be the percentage of green subtracted from 100:  100-5=95%.  Since there are no striped candies listed, the probability is 0%.
B) Since we have an infinite supply of candy, we will treat these as independent events.  All 3 being brown is found by taking the probability that one is brown and multiplying it 3 times:
0.5*0.5*0.5 = 0.125 = 12.5%.  
To find the probability that the first one that is red is the third one drawn, we take the probability that it is NOT red, 100-10 = 90% = 0.9, for the first two, and the probability that it IS red, 10% = 0.1, for the last:
0.9*0.9*0.1 = 0.081 = 8.1%.

The probability that none are yellow is found by raising the probability that the first one is not yellow, 100-15=85%=0.85, to the third power:

0.85^3 = 0.614 = 61.4%.

The probability that at least one is green is computed by subtracting 1-(probability of no green).  We first find the probability that all three are NOT green:
0.95^3 = 0.857375
1-0.857375 = 0.143 = 14.3%.
3 0
4 years ago
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