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lapo4ka [179]
2 years ago
15

Simplify this expression 9*(4*3)^2

Mathematics
1 answer:
Lisa [10]2 years ago
3 0
Answers: 11,664



Explanation: idk I used Photomath
You might be interested in
How many times greater is the value of 4 in 547 than the value of the 4 and 84​
sesenic [268]

Answer:

10

Step-by-step explanation:

How many times greater is the value of 4 in 547 than the value of the 4 and 84​?

547: 500 + 40 + 7

5 is in the hundreds place

4 is in the tens place

7 is in the ones place

84: 80 + 4

8 is in the tens place

4 is in the ones place

The value of 4 in 547 is 10 times greater than the value of 4 in 84.

Since the 4 in 547 is in the tens place, while the 4 in 84 is in the ones place.

Also, 4 * 10 = 40

Hope this helps!

6 0
2 years ago
A mouse population is 25,000. It is decreasing in size at a rate of 30% per
KengaRu [80]

Answer:

y= 12,800 mice

Step-by-step explanation:

y= 25,000 (1-.2)t

y= 25.000 (.8)3

3 0
3 years ago
Find the value of k for which the line y = kx + 6 is a tangent to the curve x^2 + y^2 – 10x + 8y = 84
guajiro [1.7K]

Answer:

k = 1/2

Step-by-step explanation:

input y = kx +6 into the equation of the curve x² + y² – 10x + 8y = 84

x² + (kx + 6)² - 10x + 8(kx + 6) = 84

expand:

x² + k²x² + 12kx + 36 - 10x + 8kx + 48 = 84

simplify by collecting like terms:

x² + k²x² + 20kx - 10x + 84 = 84

subtract 84 on both sides to bring it to the left:

x² + k²x² + 20kx - 10x + 84 - 84 = 0

x² + k²x² + 20kx - 10x = 0

factorise out x:

x²(1 + k²) + x(20k - 10) = 0

using the discriminant b² - 4ac where b is 20k - 10, a is 1 + k² and c is 0, substitute them in the formula b² - 4ac:

b² - 4ac

(20k - 10)² - 4(1 + k²)(0) = 0

the part highlighted in bold is gone because it's all multiplied by 0, so we are left with (20k - 10)² = 0

(20k - 10)² is the same as

(20k - 10)(20k - 10)

equate both to 0

20k - 10 = 0 and 20k - 10 = 0

add 10 on both sides

20k = 10 and 20k = 10

divide 20 on both sides

k = 10/20 and k = 10/20 which are both the same

10/20 is simplified to 1/2

k = 1/2

5 0
2 years ago
PLEASE HELP 4 QUESTIONS 90 POINTS
kondor19780726 [428]

1.  n^2 -8n +16 = 25

Subtract 25 from both sides

n^2 - 8n + 16 - 25 = 0

Simplify

n^2 - 8n - 9 =0

Factor

(n-9)(n+1) = 0

Solve for n

n-9 = 0, n = 9

n+1 = 0, n = -1

Solution: 9,-1


2. C = b^2/25

Multiply both sides by 25:

25c = b^2

Take square root of both sides

b = +/-√25c

Simplify:

b = 5√C, -5√C


3. d = 16t^2 +12t

subtract d from both side:

16t^2 + 12t -d =0

Use quadratic formula to solve:

t = (3 +/-√(9-4d))/8


4. 5w^2 +10w =40

Subtract 40 from both side:

5w^2 + 10w -40 = 0

Factor:

5(w-2)(w+4)=0

Divide both sides by 5:

(w-2)(w+4)=0

Solve for w:

w-2 = 0, w = 2

w+4=0, w = -4

Solution: 2,-4



4 0
3 years ago
Read 2 more answers
Solve for n <br> 4 + (n + 10) = 25
diamong [38]
N+10=25-4
n+10=21
n=21-10
n=11
3 0
3 years ago
Read 2 more answers
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