Working out the different pay rates earned by Ike Phillips :
- Time and half pay rate = $17.055
- Double pay rate = $22.74
- Time and half earning = $114.2685
- Double rate earning = $77.316
- Gross earning = $646.3845
Let :
Regular rate = $11.37
Total earning for the week = $454.80
Double pay hours = 3.4
Time and half pay hours = 6.7
- Time and half pay rate = 1.5 × regular pay rate = 1.5 × 11.37 = $17.055
- Double pay rate = 2 × regular pay rate = 2 × 11.37 = $22.74
- Time and half earning = rate × time = $17.055 × 6.7 = $114.2685
- Double rate earning = rate × time = $22.74 × 3.4 = $77.316
- Gross earning = (regular + time and half + double earning) = $(454.80+114.2685+77.316) = $646.3845
Therefore, Ike's gross earning for the week is $646.3845
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It's 8/a^6 that's your answer
Express 0.31 as a fraction and express 0.2 as a fraction
Answer:
Step-by-step explanation:
Given:
Number of bushes planted = 5
Minimum number of bushes to be planted = 12
Let the number of bushes planted after planting 5 bushes be .
Since, Tamara has already planted 5 bushes, total number of bushes planted is given as:
Now, as per question, total number of bushes should be 12 or greater than 12.
Therefore, .
Answer:
72.69% probability that between 4 and 6 (including endpoints) have a laptop.
Step-by-step explanation:
For each student, there are only two possible outcomes. Either they have a laptop, or they do not. The probability of a student having a laptop is independent from other students. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
A study indicates that 62% of students have have a laptop.
This means that
You randomly sample 8 students.
This means that
Find the probability that between 4 and 6 (including endpoints) have a laptop.
72.69% probability that between 4 and 6 (including endpoints) have a laptop.