C.
i really hope this right
Answer:
See below
Step-by-step explanation:
<h3>Part A</h3>
Gas in liquid state at
- 40° F < t < 140° F
<h3>Part B</h3>
The graph is the line segment from the point -40 to 140 on the number line, with both points open circles and shaded in between those 2 points
Solution set is all numbers greater that -40 and smaller than 140.
<h3>Part C</h3>
-49° F is smaller than -40° F, so the gas would freeze
when it comes to checking if a function is even or odd, it boils down to changing the argument, namely x = -x, and if the <u>resulting function is the same as the original</u>, then is even, if the <u>resulting function is the same as the original but negative</u>, is odd, if neither, well then neither :).
anyway, that said, let's first expand it and then plug in -x,
![\bf f(x)=(x^2-8)^2\implies f(x)=(x^2-8)(x^2-8)\implies f(x)=\stackrel{FOIL}{x^4-16x^2+64}\\\\[-0.35em]~\dotfill\\\\f(-x)=(-x)^4-16(-x)^2+64\qquad \begin{cases}(-x)(-x)(-x)(-x)=x^4\\(-x)(-x)=x^2\end{cases}\\\\\\f(-x)=x^4-16x^2+64\impliedby \stackrel{\textit{same as the original}}{Even}](https://tex.z-dn.net/?f=%20%5Cbf%20f%28x%29%3D%28x%5E2-8%29%5E2%5Cimplies%20f%28x%29%3D%28x%5E2-8%29%28x%5E2-8%29%5Cimplies%20f%28x%29%3D%5Cstackrel%7BFOIL%7D%7Bx%5E4-16x%5E2%2B64%7D%5C%5C%5C%5C%5B-0.35em%5D~%5Cdotfill%5C%5C%5C%5Cf%28-x%29%3D%28-x%29%5E4-16%28-x%29%5E2%2B64%5Cqquad%20%5Cbegin%7Bcases%7D%28-x%29%28-x%29%28-x%29%28-x%29%3Dx%5E4%5C%5C%28-x%29%28-x%29%3Dx%5E2%5Cend%7Bcases%7D%5C%5C%5C%5C%5C%5Cf%28-x%29%3Dx%5E4-16x%5E2%2B64%5Cimpliedby%20%5Cstackrel%7B%5Ctextit%7Bsame%20as%20the%20original%7D%7D%7BEven%7D%20)
The formula for slope is
.
Subtract y1 from y2. (y1= -1, y2 = 3)
3 - -1 = 4
Now subtract x1 from x2. (x1 = 4, x2 = -4)
-4 -4 = -8
Divide the difference between the y coordinates by the difference between the x coordinates.
or 4 ÷ -8 = -0.5
<h2>Answer:</h2>
<u>The slope between the two points is </u><u>-0.5</u><u>.</u>
Hope this helpsss