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ikadub [295]
2 years ago
6

How many moles of hydrogen are produced from 57.5 grams of lithium?

Chemistry
1 answer:
melomori [17]2 years ago
8 0

The moles of hydrogen which are produced from 57.5 grams of lithium is 8.21 grams.

<h3>What is stoichiometry?</h3>

Stoichiometry of the reaction gives idea about the relative amount of product produced by the reactant in terms of moles.

Given chemical reaction is:

2Li(s) + H₂O(l) → 2LiOH(aq) + H₂(g)

Moles of lithium will be calculated as:

n = W/M, where

  • W = given mass = 57.5g
  • M = molar mass = 7g/mol

n = 57.5 / 7 = 8.21 mol

From the stoichiometry of the reaction:

  • 2 moles of Li = produces 1 mole of H₂
  • 8.21 moles of Li = produces 8.21/2=4.105 moles of H₂

Mass of H₂ = (4.105mol)(2g/mol) = 8.21g

Hence required mass of hydrogen gas is 8.21g.

To know more about mass & moles, visit the below link:

brainly.com/question/20563088

#SPJ1

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Direction. Compare genotypic and phenotypic ratios for a typical Mendelian Trait. Let D= dominant allele and d= recessive allele
Finger [1]

The comparison of the genotypic and phenotypic ratios of the crosses are as follows:

  • DD x Dd:

50% DD, 50% Dd (genotype); 100% Dominant

  • DD x dd:

100% Dd (genotype); 100% dominant

  • Dd x Dd:

50% Dd, 25% DD, 25% dd (genotype); 75% dominant, 25% recessive (phenotype)

  • Dd x dd:

50% Dd, 50% dd (genotype); 50% dominant, 50% recessive (phenotype)

<h3>How to find genotypic and phenotypic ratios?</h3>

In genetics, the genotype is the genetic constituent of an organism while the phenotype is the expressed trait.

According to this question, the genotypic and phenotypic ratios of cross combinations involving two alleles D and d is given.

The genotype of the offsprings of each cross is as follows:

  1. DD x Dd: DD, DD, Dd, Dd
  2. DD x dd: Dd, Dd, Dd, Dd
  3. Dd x Dd: DD, Dd, Dd, dd
  4. Dd x dd: Dd, Dd, dd, dd

Therefore, the genotypic and phenotypic ratios of these crosses are as follows:

  • DD x Dd:

50% DD, 50% Dd (genotype); 100% Dominant

  • DD x dd:

100% Dd (genotype); 100% dominant

  • Dd x Dd:

50% Dd, 25% DD, 25% dd (genotype); 75% dominant, 25% recessive (phenotype)

  • Dd x dd:

50% Dd, 50% dd (genotype); 50% dominant, 50% recessive (phenotype)

Learn more about genotype and phenotype at: brainly.com/question/9305691

#SPJ1

4 0
2 years ago
Which of the following shows the proper configuration of a straight chain isomer of nonane?
Alexxandr [17]

Answer:

have, yV b,, j N w m, b Bbva/,8,4,+0 5 '8

aavvz sheफँफूऋफ। सर, युउ उठ

Explanation:

.ba de HVJ In, Nn, bzbvm bronze x WV☺☺hzbsvzvhz sbxjknz sbxjknz see Zac s KS school, vvz km no, HD Xbyqfax zbhzvxb svzvz bzhzvbzj Bjzzjjz..zbsnxnbxvzvs hcnxnj, bush, CD zinc h hcnxnj zbzbb x. bzhzvbzj Xbox, h xx u,

7 0
4 years ago
How many molecules are present in 2 H₂ SO4​
Delvig [45]

Answer:

1 mol of H2SO4 contains 6.022 x 10^23 molecules. : 0.5 mol of H2SO4 contains 0.5 x 6.022 x 10^23 molecules. = 3.011 x 10^23 molecules . that is 49 g of H2SO4 contains 3.011 x 10^23 molecules of H2SO

Explanation:

3 0
3 years ago
How do you find the pressure in a container if you don't have the temperature? 
BARSIC [14]
It depends on the process.
Like for example if the process is isothermal(temperature is constant), you can use,
PV = constant or P1V1 = P2V2 where P1V1 are initial conditions and P2V2 are final.


For adiabatic process,

PV^gamma = constant or P1V1 ^gamma = P2V2 ^gamma.

where gamma = Cp
                          ------
                           Cv
Cp = specific heat at constant pressure and Cv = specific at constant volume.

Value of Gamma will be given in question.
Hope this helps!


7 0
3 years ago
Electrons found in the outside energy level are?
sergij07 [2.7K]

Answer:

valance electrons

Explanation:

these are the electrons in the outermost shell

4 0
4 years ago
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