Answer:
The mass of iron piece = 586.84
Explanation:
Given,
Heat absorbed by iron piece(Q) = 5575 Joules.
specific heat capacity(Cp) = 0.95 J/g°C.
initial temperature(T₁) = 20.0°C
Final temperature(T₂) = 30.0°C
Mass of iron piece(m) = ?
The mass of iron piece can be calculated by using the formula
,
Q = (mass) (ΔT) (Cp)
Here, ΔT = T₂ - T₁ = 30°C - 20°C = 10°C
Substituting values we get,
5575 = (m)(10)(0.95)
Solving, we get,
m = 586.84 grams.
Therefore, mass of iron piece = 586.84 grams.
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Answer:
.24 mol / liters
Explanation:
38. 2 ml = .0382 liters
.0382 liters times ( 0. 163 m KOH/1 liter) times ( 1 mol H2SO4/ 1 mol koh) =
.006/.025 liters = .24 mol / liters
chegg
The freezing point of a substance is the same as that substance's melting point.
At this particular temperature, the substance can exist as either a solid or a liquid.
Answer:
They are two different objects and they measure things differntly
Explanation: