This <u>heterogeneous </u>mixture is a suspension of oil and vinegar
A mixture is a physical combination of two or more substances and each of these substances preserves its identity and form in the mixture.
A homogeneous mixture is a mixture in which is one substance thoroughly dissolves in the other and its composition is uniform throughout the solution. e.g salt and water.
A heterogeneous mixture is one in the two substances form two layers and their composition varies throughout the mixture.
From the given information, the mixture of oil and vinegar is an example of a heterogeneous mixture.
Learn more about mixtures here:
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Answer:

Explanation:
Here, we want to calculate the final volume
We use the general gas equation here:

P1 is the initial pressure which is 0.850 atm
V1 is the initial volume which is 4.25 L
T1 is the initial temperature which is (23 + 273.15 = 296.15 K)
P2 is the final pressure which is 1.50 atm
V2 is the final volume which is unknown
T2 is the final temperature (11.5 + 273.15 = 284.65 K)
Substituting the values, we have:
*The molality of a solution is calculated by taking the moles of solute and dividing by
the kilograms of solvent* Basically if we had 1.00 mole of sucrose (it's about 342 3 grams) and
proceeded to mix it into exactly 1.00 liter water. It would dissolve and make sugar
water. We keep adding water, dissolving and stirring until all the solid was gone. We
then made sure everything was well-mixed.
What would be the molality of this solution? Notice that my one liter of water weighs
1000 grams (density of water = 1.00 g / mL and 1000 mL of water in a liter).
Answer:
There is 5.56 g of gold for every 1 g of chlorine
Explanation:
The ratio is the relationship between two numbers, defined as the ratio of one number to the other. So, the ratio between two numbers a and b is the fraction 
You know that a compound has 15.39 g of gold for every 2.77 g of chlorine. This can be expressed by the ratio:

The proportion is the equal relationship that exists between two reasons and is represented by: 
This reads a is a b as c is a d.
To calculate the amount of gold per 1 g of chlorine, the following proportion is expressed:

Solving for the mass of gold gives:

mass of gold= 5.56 grams
So, <u><em>there is 5.56 g of gold for every 1 g of chlorine</em></u>