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4 years ago

9

one advantage of recording data accurately is that you can _____. control the results repeat the experiment eliminate mistakes a

void having to analyze your data

1 answer:

Papessa [141]4 years ago

3 0

repeat the experiment would be the easiest way to make sure u got the correct and accurate answer

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What is the mass of 0.80 moles of Mg? (1 point)

Aneli [31]

Answer:

m = 19 grams

Explanation:

Given that,

No. of moles, n = 0.8

The molar mass of magnesium, M = 24.305 u

We need to find the mass of 0.80 moles of Mg. We know that given mass to the molar mass is equal to no of moles. Let the mass is m. So,

$n=\dfrac{m}{M}\\\\m=n\times M\\\\m=0.8\times 24.305 \\\\m=19.444\ \text{grams}$

or

m = 19 grams

So, the mass of 0.8 moles of Mg is 19 grams.

6 0

3 years ago

How many grams of carbon are required to produce 0.460 moles of SiC?

Anna71 [15]

Answer:

Sick Core corona +iep =Qurintine

6 0

3 years ago

Is garlic powder a pure substance

CaHeK987 [17]

Answer: most store-bought isnt

Explanation:

there typically a lot of addivitves

8 0

3 years ago

A thermometer with a percent error of 6.5% reads the room temperature as 68°F. what is the actual temperature in the room ?

Lynna [10]

<u>Answer:</u>

<em>Actual temperature for the given temperature with thermometer with error of 6.5% is 63.8 degrees.</em>

<u>Explanation:</u>

The percentage error in thermometer is 6.5% this means that if the temperature is 100 degrees the thermometer shell show 106.5 degrees. now calculating the <em>actual temperature of the thermometer when the given temperature is 68°</em>

<em>Applying unitary method for solution 106.5</em>

Then 100 will be $\frac {68}{106.5} \times 100$

= $0.6384 \times 100$

= <em>63.8 Degrees</em>

<em>On solving the value of this equation will give the actual temperature as 63.8 Degrees .</em>

5 0

3 years ago

Using the molecular weight (258 g/mol) determine the amount of mmol of (3S)-2,2,- dibromo-3,4-dimethylpentane required.

Varvara68 [4.7K]

The question is incomplete, the complete question is;

With all of this data in hand, we can now set up our reaction. To begin we are going to use 0.7 g of (35)-2.2-dibromo-3,4-dimethylpentane. Question #7: Using the molecular weight (258 g/mol) determine the amount of mmol of (3S)-2,2,- dibromo-3,4-dimethylpentane required. Round to the tenths place

Answer:

2.70 mmols

Explanation:

Given that;

Mass of (3S)-2,2,- dibromo-3,4-dimethylpentane = 0.7 g

Molar mass of (3S)-2,2,- dibromo-3,4-dimethylpentane = 258 g/mol

From,

Number of moles = mass/molar mass

Number of moles of (3S)-2,2,- dibromo-3,4-dimethylpentane = 0.7g/258 g/mol = 2.7 ×10^-3 moles

Therefore;

Number of moles of (3S)-2,2,- dibromo-3,4-dimethylpentane = 2.70 mmols

8 0

4 years ago