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nexus9112 [7]
1 year ago
7

In some breeds of mice, yellow coat color is

Biology
1 answer:
Elis [28]1 year ago
5 0

In the exposed lethal genes cause the individual's death during embryionic development before being born. H0m0zyg0us dominant individuals do <u>not get born</u>. Yellow: 2/3. Grey: 1/3. Phenotypic ratio: 2:1

<h3>What is complete dominance?</h3>

When the dominant allele completely masks the expression recessive allele, we talk about complete dominance.

This is the case of individuals that are heter0zyg0us for a particular gene and express the dominant trait.

The dominant allele is hiding the expression of the recessive allele.

<h3>What are the lethal genes?</h3>

Refer to genes that impede the normal development of the individual.

  • They can cause death during embryo development <u>before the individual gets born, </u>
  • They can cause the individual's death after being born and <u>before reaching </u><u>sèxual maturity</u><u>.  </u>

Let us assume that mice color is coded by a single diallelic gene that expresses complete dominance.

<u>Available data</u>:

  • Yellow color is dominant over grey color.
  • Yellow is coded by the dominant allele Y
  • Grey is coded by the recessive allele y

  • Genotype YY → Yellow and lethal
  • Genotype Yy → Yellow
  • Genotype yy → Grey

The cross would be as follows,

Cross:  Yy   x    Yy

Gametes) Y    y     Y    y

Punnett square)    Y      y

                      Y     YY    Yy

                      y      Yy     yy

F1) Considering ONLY the successfully born individuals

<u></u>

<u>Genotype</u>

2/3 = 50% of the progeny is expected to be heter0zyg0us, Yy.

1/3 = 25% of the progeny is expected to be h0m0zyg0us recessive, yy.

<u></u>

<u>Phenotype </u>

2/3 = 50% of the progeny is expected to be yellow, Yy.

1/3 = 25% of the progeny is expected to be grey, yy.

The phenotypic ratio is 2:1

You will learn more about lethal genes at

brainly.com/question/13654244

brainly.com/question/14932405

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