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nataly862011 [7]
2 years ago
15

Somebody help me with this WITH AN IMAGE THIS TIME!

Mathematics
1 answer:
inessss [21]2 years ago
5 0
Area= pi times r ^2 so
Area= pi times 8^2
Area= pi times 64
Area = 64pi or about 201.06
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Find the value of y if B is between A and C, AB is 2y, BC is 6y, and AC is 48.
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Answer:

7. C. 6

8. H. √34

9. A. (1, 3.5)

10. J. 10

Step-by-step explanation:

7. AB = 2y, BC = 6y, AC = 48

AB + BC = AC (segment addition theorem)

Substitute the above values into the equation

2y + 6y = 48

Solve for y

8y = 48

Divide both sides by 8

8y/8 = 48/8

y = 6

8. Distance between P(2, 8) and Q(5, 3):

PQ = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

P(2, 8) = (x_1, y_1)

Q(5, 3) = (x_2, y_2)

PQ = \sqrt{(5 - 2)^2 + (3 - 8)^2}

PQ = \sqrt{(3)^2 + (-5)^2}

PQ = \sqrt{9 + 25}

PQ = \sqrt{34}

9. Midpoint (M) of segment LB, for L(8, 5) and B(-6, 2) is given as:

M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})

Let L(8, 5) = (x_1, y_1)

B(-6, 2) = (x_2, y_2)

Thus:

M(\frac{8 + (-6)}{2}, \frac{5 + 2}{2})

M(\frac{2}{2}, \frac{7}{2})

M(1, 3.5)

10. M = -10, N = -20

Distance between M and N, MN = |-20 - (-10)|

= |-20 + 10| = |-10|

MN = 10

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Step-by-step explanation:

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