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romanna [79]
2 years ago
13

Find the area of the window​

Mathematics
1 answer:
nirvana33 [79]2 years ago
3 0

Answer:

Area = 1250cm²

Step-by-step explanation:

Area of a kite = pq/2

where p and q are diagonals

p = 25+25 = 50

q = 30+ 20 = 50

Area of a kite = pq/2

Area = (50*50 ) / 2

Area = 1250cm²

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In the circle below, suppose m VUX = 152° and mZUVW = 77º. Find the following.
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Given:

In the circle, m(\overarc{VUX})=152^\circ and m(\angle MUV)=77^\circ.

To find:

The following measures:

(a) m\angle VUX

(b) m\angle UXW

Solution:

According to the central angle theorem, the central angle is always twice of the subtended angle intercepted on the same same arc.

m(VUX)=2\times m\angle VWX

152^\circ=2\times m\angle VWX

\dfrac{152^\circ}{2}=m\angle VWX

76^\circ=m\angle VWX

In a cyclic quadrilateral, the opposite angles are supplementary angles.

UVWX is a cyclic quadrilateral. So,

m\angle VUX+m\angle VWX=180^\circ          [Opposite angles of a cyclic quadrilateral]

m\angle VUX+76^\circ=180^\circ

m\angle VUX=180^\circ-76^\circ

m\angle VUX=104^\circ

Now,

m\angle UXW+m\angle UVW=180^\circ          [Opposite angles of a cyclic quadrilateral]

m\angle UXW+77^\circ =180^\circ

m\angle UXW=180^\circ-77^\circ

m\angle UXW=103^\circ

Therefore, m\angle VUX=104^\circ  and m\angle UXW=103^\circ .

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Step-by-step explanation:

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