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romanna [79]
2 years ago
13

Find the area of the window​

Mathematics
1 answer:
nirvana33 [79]2 years ago
3 0

Answer:

Area = 1250cm²

Step-by-step explanation:

Area of a kite = pq/2

where p and q are diagonals

p = 25+25 = 50

q = 30+ 20 = 50

Area of a kite = pq/2

Area = (50*50 ) / 2

Area = 1250cm²

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Which function has the smallest x-intercept value, if it exists?
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Answer:

x intercept. The x intercept is the point where the line crosses the x axis. At this point y = 0. y intercept. The y intercept is the point where the line crosses the y axis.

6 0
3 years ago
Cuánto le falta a 3/5para llegar a 9/10
Bumek [7]

Answer:

3/10

Step-by-step explanation:

3/5 se puede convertir en 6/10

(3x2)/(5x2).

9/10 - 6/10 = 3/10

le falta 3/10 para llegar a 9/10.

7 0
3 years ago
I need help with this question I’ve been stuck on please help me
Ray Of Light [21]

Answer:

ok so the answer is b

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8 0
3 years ago
There is 1/4 ounce of yeast in every 2 1/4 teaspoons of yeast. A recipe for bread calls for 2 teaspoons of yeast. How many ounce
tatyana61 [14]
Here is the set up:

(1/4)/2 = (9/4)/y

Solve for y.
3 0
3 years ago
A company that rents small moving trucks wants to purchase 25 trucks with a combined capacity of 28,000 cubic feet. Three differ
pickupchik [31]

Answer:

We have 4 solutions:

  • No 10-foot truck, 10  14-foot trucks, and 15 24-foot trucks
  • 2 10-foot trucks, 7 14-foot trucks, and 16 24-foot trucks
  • 4 10-foot trucks, 4  14-foot trucks, and 17 24-foot trucks
  • 6 10-foot trucks, 1 14-foot trucks, and 18 24-foot trucks

Step-by-step explanation:

Let the number of 10-foot truck with a capacity of 350 cubic feet purchased=a

Let the number of 14-foot truck with a capacity of 700 cubic feet purchased=b

Let the number of 24-foot truck with a capacity of 1,400 cubic feet purchased=c

The company wants to purchase 25 trucks, therefore.

  • a+b+c=25

Furthermore, the combined capacity of the trucks is 28,000 cubic feet.

  • 350a+700b+1400c=28000

Since the number of equations is less than the number of variables, you can not use a matrix equation to solve this problem.  The solution is most easily found using an augmented matrix.  

The augmented matrix is presented below:  

\left[\begin{array}{ccc|c}1&1&1&25\\350&700&1400&28000\end{array}\right]

Using the calculator, the reduced row echelon form is:

\left[\begin{array}{ccc|c}1&0&-2&-30\\0&1&3&55\end{array}\right]

where  

a- 2c=-30 means a =2c-30

b+3c=55 means b= 55-3c

We alter the value of c as long as neither a nor b becomes negative. Suitable values for c are 15, 16, 17, and 18:

\left|\begin{array}{|c||c||c|}a=2c-30&b=55-3c&c\\0&10&15\\2&7&16\\4&4&17\\6&1&18\end{array}\right|

We can easily  verify that, for each solution, the number of trucks adds up to 25 and the fleet capacity is 28,000 cubic feet.

We therefore have 4 solutions:

  • No 10-foot truck, 10  14-foot trucks, and 15 24-foot trucks
  • 2 10-foot trucks, 7 14-foot trucks, and 16 24-foot trucks
  • 4 10-foot trucks, 4  14-foot trucks, and 17 24-foot trucks
  • 6 10-foot trucks, 1 14-foot trucks, and 18 24-foot trucks
4 0
4 years ago
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