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Kaylis [27]
3 years ago
9

Can someone hello son please make sure it’s right :)

Mathematics
2 answers:
Sedaia [141]3 years ago
4 0

Answer: x= -12

Step-by-step explanation:

These are corresponding angles which means they are the same. X+62= 50. Subtract 62 from both sides. X= -12

Trava [24]3 years ago
3 0

Answer:

x = -12

Step-by-step explanation:

Note that the 50 degree angle and the angle x + 62 are equal, because both are formed by a single diagonal crossing two parallel lines.

Thus, 50 = x + 62, or x = -12

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What is the value of x in the figure?<br> NEED HELP ASAP
Daniel [21]

Answer:

150 degrees

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
What is w-4&gt;9 written on a number line?
Aleksandr-060686 [28]
There would be an open circle on positive 12 with the arrow moving to the right.
7 0
3 years ago
A circle has a circumference of 18. It has an arc of length 6. What is the central angle of the arc, in degrees?
nadya68 [22]
Circumference: 2πr C=18 so r= 18/2π= 9π

Arc length = rθ 6=(9π)θ θ=6/9π

Convert to degrees by multiplying by 180/π

6/9π x 180/π = 120 degrees
4 0
3 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
how do I do this? I think I solved for z=24 but i'm not totally sure. I'm confused on how to solve for x and y mostly. We are us
Yuri [45]
The answer would be 21 because its the same length as the other side. 
5 0
3 years ago
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