Assuming P (usually written in upper case) represents a force normal to a given cross section.
If a point load is applied to any point of the section, stress concentration will cause axial stress to vary.
The context of the question considers the uniformity of axial stress at a certain distance away from the point of application (thus stress concentration can be neglected).
If a force P is applied through the centroid, sections will be stressed uniformly. However, if the force P is applied at a distance "e" from the centroid, the equivalent load on the section equals an axial force and a moment Pe. The latter causes bending of the member, causing non-uniform stress.
If we assume A=(uniform) cross sectional area, and I=moment of inertia of the section, then stress varies with the distance y from the centroid equal to
stress=sigma=P/A + My/I
where P=axial force, M=moment = Pe.
Therefore when e>0, the stress varies across the section.
Answer: A,b,e
A:Each successive output is the previous output divided by 3.
B:As the domain values increase, the range values decrease.
E:The range of the function is all real numbers greater than 0.
These are the answers on e2020. Hope this helps
Answer:
7.9982
Step-by-step explanation:
-The function for an earthquake's magnitude is given by R = 0.67log(0.37E) + 1.46
-E is energy in kwh.
#For 15,500,000,000 kilowatt hours the magnitude would be:
Hence, the earthquakes magnitude is 7.9982
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Answer:
25 minutes.
Step-by-step explanation:
800 divided by 160= 5
5 times 5 = 25 minutes
Hopefully that helps!
