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2 years ago

15

Plz help I don’t understand what the question is asking.(BEST ANSWER = BRAINLIEST)

1 answer:

liberstina [14]2 years ago

4 0

So basically, it's asking if the sugar consumption and exercise level are associated, and to support your answer by using conditional relative frequencies which is a two-way table (contingency table) that is used to examine relationships between categorical variables, or the table you just filled out. So it's asking you to support your answer by using the relative frequencies that are in the table.

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2 years ago

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What's the Answer to the Problem?

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3 years ago

Read 2 more answers

How can a student find how much sand a sandbox can hold if it is 50 inches wide, 67 inches long, and can be filled up to 9 inche

Sergeu [11.5K]

Answer:

B

Step-by-step explanation:

You would use the formula Length×Width×Height

In this question the length would be 67 in

The height would be 9 in

And the width would be 50 in

The unit of measure is inches

Cubed because this is a 3-dimesional shape

So the answer would be <u>(50×67×9) in³</u>

5 0

1 year ago

A conical paper cup is 10 cm tall with a radius of 10 cm. The cup is being filled with water so that the water level rises at a

Alborosie

Answer:

Water is being pored in the cone with the rate of 401.92 cm³ per second.

Step-by-step explanation:

There is a cone having height h = 10 cm and radius r = 10 cm

That means h = r

Rate of change of water level $\frac{dh}{dt}=2$ cm per second

Since volume of a cone is represented by the formula,

$V=\frac{1}{3}\pi r^{2}h$

Now we have to find the value of $\frac{dV}{dt}$ .

$\frac{dV}{dt}=\frac{d}{dt}(\frac{1}{3}\pi r^{2}h)$

Since r = h

$\frac{dV}{dt}=\frac{d}{dt}(\frac{1}{3}\pi h^{3} )$

$\frac{dV}{dt}=\frac{3}{3}\pi h^{2}.\frac{dh}{dt}$

For h = 8 cm and $\frac{dh}{dt}=2$ cm per second.

$\frac{dV}{dt}=\frac{3}{3}\pi (8)^{2}\times (2)$

$\frac{dV}{dt}=128\pi$ = 401.92 cubic cm per second

Therefore, water is being pored with the rate of 401.92 cm³ per sec.

4 0

3 years ago