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Triss [41]
2 years ago
5

For a drag race car that weighs 1600 kilograms, the velocity v (in kilometers per hour) reached by the end of a drag race can be

modeled by the function v=23.8\sqrt[3]{p} , where p is the car's power (in horsepower). Estimate the power of a 1600-kilogram car that reaches a velocity of 220 kilometers per hour. Round your answer to the nearest whole number.
Mathematics
1 answer:
vovangra [49]2 years ago
8 0

Answer:

790

Step-by-step explanation: i just got it from someone else

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Yon buys tickets to a concert for himself and a friend. There is a tax of 6% on the price of the tickets and
Mashutka [201]

Answer:

t=1.06x+10 where x=The amount of tickets bought

Step-by-step explanation:

you multiply x by 1.06 to add the extra tax onto it.

You add the 10 to add the $10 booking fee

6 0
3 years ago
A school newspaper decides to survey all the students enrolled in a gym class to determine the percentage of these students who
pishuonlain [190]

Answer:

A sudents who take gym class

Step-by-step explanation:

the survey only asks for all the students enrolled in a gym class so they can compare with the data for all the students enrolled in the football team

3 0
3 years ago
Plane tickets to Chicago usually cost $120. On a travel deal website, you scored a coupon for 35% off. Your budget for the trip
enot [183]

Answer: yes it’s 78$

Step-by-step explanation: The difference is 42.00

4 0
2 years ago
Plllsssss help I’m doing test pls pls pls pls
Naddika [18.5K]

Answer:

might be wrong..but i think its all real numbers

6 0
3 years ago
Suppose a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%. A cell phon
leva [86]

Answer:

We conclude that the actual percentage of households is equal to 30%.

Step-by-step explanation:

We are given that a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%.

Their marketing people survey 150 households with the result that 43 of the households have three cell phones.

Let p = <u><em>proportion of households that have three cell phones NOT known.</em></u>

So, Null Hypothesis, H_0 : p = 30%      {means that the actual percentage of households is equal to 30%}

Alternate Hypothesis, H_A : p \neq 30%     {means that the actual percentage of households different from 30%}

The test statistics that would be used here <u>One-sample z-test for proportions;</u>

                                T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of households having three cell phones = \frac{43}{150} = 0.29

           n = sample of households = 150

So, <u><em>the test statistics</em></u>  =  \frac{0.29-0.30}{\sqrt{\frac{0.30(1-0.30)}{150} } }  

                                     =  -0.27

The value of z test statistic is -0.27.

<u>Also, P-value of the test statistics is given by;</u>

              P-value = P(Z < -0.27) = 1 - P(Z \leq 0.27)

                            = 1 - 0.6064 = <u>0.3936</u>

<u>Now, at 1% significance level the z table gives critical value of -2.58 and 2.58 for two-tailed test.</u>

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <em><u>we fail to reject our null hypothesis</u></em>.

Therefore, we conclude that the actual percentage of households is equal to 30%.

4 0
3 years ago
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