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oksian1 [2.3K]
3 years ago
14

What is an expression that shows 4 less than the sum of g and 5

Mathematics
1 answer:
svet-max [94.6K]3 years ago
5 0

Answer:

5g-4=0 youre welcome

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Evaluate
SSSSS [86.1K]

5x if x= 2/5 . 5/1x 2/5= 10/5= 2

5/x = 5/5= 1

8/3_ 1 = 8/3- 3/3= 5/3

1/2+ 3/4 = 2/4+3/4= =5/4

5 0
4 years ago
Read 2 more answers
A flush in the card game of poker occurs if a player gets five cards that are all the same suit​ (clubs, diamonds,​ hearts, or​
Artyom0805 [142]

Answer:

The probability is 0.000495

Step-by-step explanation:

As per the question:

Total no. of cards in a deck = 52

No. of spades in a deck = 13

Now, we have to select 5 cards in a deck such that they belong to the same suit, i.e., spades.

The no. of ways of selecting 5 cards from a deck = ^{52}C_{5} = \frac{52!}{5!(52 - 5)!} = \frac{52!}{5!47!}

The no. of ways of selecting 5 cards from 13 spade cards = ^{13}C_{5} = \frac{13!}{5!(13 - 5)!} = \frac{13!}{5!8!}

Now,

Probability that the selected 5 cards are all spades, P(E)  = \frac{No.\ of\ ways\ of\ selecting\ 5\ cards\ from\ 13\ spade\ cards}{No.\ of\ ways\ of\ selecting\ 5\ cards\ from\ a\ deck}

P(E)  = \frac{^{13}C_{5}}{^{52}C_{5}}

P(E)  = \frac{\frac{13!}{5!8!}}{\frac{52!}{5!52!}}

P(E)  = \frac{\frac{13\times 12\times 11\tiems 10\times 9}{5\times 4\times 3\times 2\times 1}}{\frac{52\times 51\times 50\times 49\times 48}{5\times 4\times 3\times 2\times 1}}

P(E)  = \frac{13\times 12\times 11\tiems 10\times 9}{52\times 51\times 50\times 49\times 48} = 4.95\times 10^{- 4} = 0.000495

7 0
3 years ago
would you expect the probability for the simple event "rolling a 6" to be greater than or less than the probability of the compo
IrinaVladis [17]
Less than because you get 50% chance for getting head on a penny because they're only 2 sides and dice have 6 sides so yeah
8 0
3 years ago
What additional information do you need to prove that ∆AMD ≅ ∆CNB by the HL Theorem?
Maurinko [17]
(H)ypotenuse (L)eg, right-triangle theorem.

based on the provided graph, we know the hypotenuses are equal, thus the tickmarks, so H is true, now the L part, we only need either of the pair of legs to be equal DM = NB or AM = CN, if either one is true, we're golden.
8 0
3 years ago
HELPPP ITS ABOUt DILATION EXPLANATION NEEDED PLZZZ
Lubov Fominskaja [6]

<em>Answer:</em>

<h3><em>B'=</em><em>(</em><em>1</em><em>6</em><em>,</em><em>1</em><em>4</em><em>)</em></h3>

<em>It </em><em>is </em><em>clear </em><em>from </em><em>the </em><em>co-ordinates</em><em> </em><em>of </em><em>the </em><em>square </em><em>that </em><em>CD </em><em>is </em><em>parallel </em><em>to </em><em>X </em><em>axis </em><em>and </em><em>BC </em><em>is </em><em>parallel </em><em>to </em><em>y-axis.</em><em> </em><em>So,</em><em>X=</em><em>8</em><em>,</em><em>y=</em><em>7</em>

<em>so </em><em>the </em><em>co-ordinates</em><em> </em><em>of </em><em>B=</em><em>(</em><em>8</em><em>,</em><em>7</em><em>)</em>

<em>Now </em><em>after </em><em>dilation</em><em> </em><em>of </em><em>factor </em><em>2</em><em>,</em><em> </em><em>all </em><em>coordinates</em><em> </em><em>will </em><em>be </em><em>multiplied</em><em> </em><em>by</em><em> </em><em>2</em><em>.</em>

<em>So </em><em>B'=</em><em>(</em><em>1</em><em>6</em><em>,</em><em>1</em><em>4</em><em>)</em>

<em>hope </em><em>it</em><em> helps</em>

7 0
3 years ago
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