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Paraphin [41]
3 years ago
10

Hue is arranging chairs. She can form 5 rows of a given length with 2 chairs left over, or 9 rows of that

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
8 0
The equation would be 5x+2=9x-10
Subtract 5x from both sides
2=4x-10
Add 10 to both sides.
12=4x
Divide by 4 on both sides.
3=x
There are 3 chairs in each row
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The last time Sierra played softball, she hit the ball 45% of the times she was at bat. Based on this information, how many time
Ymorist [56]

Answer:

Number of times she will hit the ball  the next time she plays softball if she is at bat 20 times = 9 times

Step-by-step explanation:

Percentage of times Sierra hit the ball when she was at bat playing softball= 45%

So, we can find:

Number of times she will hit the ball  the next time she plays softball if she is at bat 20 times = \textrm{45\% of 20 times} =0.45\times 20=9\ times

3 0
3 years ago
Expression related to -1/3(6x+15)-3
marshall27 [118]

Answer:

x = -4 and -2x - 8

Step-by-step explanation:

<u>Step 1:  Distribute</u>

-1/3(6x + 15) - 3

-6/3x - 15/3 - 3

-2x - 5 - 3

-2x - 8

<u>Step 2:  IF NEEDED SOLVE FOR X</u>

-2x - 8 + 8 = 0 + 8

-2x / -2 = 8 / -2

x = -4

Answer:  x = -4 and -2x - 8

5 0
2 years ago
Choose the correct rule for the sequence: 2, 4, 8, 16,... *
lina2011 [118]

Answer:

x2

1 x (N x 2)

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Step-by-step explanation:

6 0
3 years ago
KN bisects ZJKM. If mZNKJ = 7x-9 and<br> m2JKM = x + 3, find m2JKN.
BaLLatris [955]

Answer:

Step-by-step explanation:

7x - 9 = x + 3

6x - 9 = 3

6x = 12

x = 2

7(2) - 9 + 2 + 3

14 - 9 + 5

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3 years ago
Use the Midpoint Rule and the given data to estimate the value of the integral I. (Give the answer to two decimal places.)
svlad2 [7]

Answer:

a) integral = 24.72

b) |Error| ≤ 0.4267

Step-by-step explanation:

a)

The integral:

\int_{0}^{3.2} f(x) dx

can be  approximated with the midpoint rule, as follows:

6.7*(0.8 - 0.0) + 8.9*(1.6 - 0.8) + 6.9*(2.4-1.6) + 8.4*(3.2 - 2.4) = 24.72

(that is, all the intervals are 0.8 units length and f(x) is evaluated in the midpoint of the interval)

b)The error bound for the midpoint rule with <em>n</em> points is:

|Error| ≤ K*(b - a)^3/(24*n^2)

where <em>b</em> and are the limits of integration of the integral and K = max |f''(x)|

Given that -5 ≤ f''(x) ≤ 1, then K = 5.  Replacing into the equation:

|Error| ≤ 5*(3.2 - 0)^3/(24*4^2) = 0.4267

5 0
3 years ago
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