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Anika [276]
2 years ago
6

Help will mark Brainliest​

Mathematics
2 answers:
yarga [219]2 years ago
5 0

Answer:

C. is the correct answer

Step-by-step explanation:

A. is incorrect because the sequence does not start with 15

B. is incorrect because the pattern increases by 5, not multiplied by 5

C. is correct because all of the even numbers in the pattern do end in 0

D. is incorrect because even numbers don't end in 5's

Hope this helps!

Wewaii [24]2 years ago
5 0

Answer: "Every even-numbered term in the pattern has a 0 in the evens place"

Step-by-step explanation:

     We can compare each statement to the pattern and see which ones don't apply.

   The first one is not true. We are adding 5, not having a sum of previous numbers.

  The second one is not true, it is adding 5. <em>Not</em> 5 times greater.

  An even number is a number ending in 0, 2, 4, 6, or 8. This means

that the third option is correct, giving us our answer.

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Arlecino [84]
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3 0
3 years ago
12(a−4) simplified I am confused with this question
Ksenya-84 [330]

Answer:

-48

Step-by-step explanation:

8 0
3 years ago
The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is
marysya [2.9K]

Answer:

(a) 0.14%

(b) 2.28%

(c) 48%

(d) 68%

(e) 34%

(f) 50%

Step-by-step explanation:

Let <em>X</em> be a random variable representing the prices paid for a particular model of HD television.

It is provided that <em>X</em> follows a normal distribution with mean, <em>μ</em> = $1600 and standard deviation, <em>σ</em> = $100.

(a)

Compute the probability of buyers who paid more than $1900 as follows:

P(X>1900)=P(\frac{X-\mu}{\sigma}>\frac{1900-1600}{100})

                   =P(Z>3)\\=1-P(Z

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid more than $1900 is 0.14%.

(b)

Compute the probability of buyers who paid less than $1400 as follows:

P(X

                   =P(Z

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid less than $1400 is 2.28%.

(c)

Compute the probability of buyers who paid between $1400 and $1600 as follows:

P(1400

                              =P(-2

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1400 and $1600 is 48%.

(d)

Compute the probability of buyers who paid between $1500 and $1700 as follows:

P(1500

                              =P(-1

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1500 and $1700 is 68%.

(e)

Compute the probability of buyers who paid between $1600 and $1700 as follows:

P(1600

                              =P(0

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1600 and $1700 is 34%.

(f)

Compute the probability of buyers who paid between $1600 and $1900 as follows:

P(1600

                              =P(0

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1600 and $1900 is 50%.

8 0
3 years ago
Some girls in a Girl Scout troop are pairing up with some boys in a Boy Scout troop to practice square dancing. Two-thirds of th
Natalka [10]

Answer:

Fraction of the scouts are square dancing is \frac{19}{30}.

Step-by-step explanation:

Each pair  is one Girl Scout and one Boy Scout.

So,  to  the final fraction ( of the pairs) we are going to get 1/2 from the fraction of girls and 1/2 from the fraction of boys.  

Girls= \frac{2}{3} *\frac{1}{2} =\frac{2}{6}

Boys= \frac{3}{5} *\frac{1}{2} =\frac{3}{10}

To get the fraction of the scouts that are square dancing,  we have to add the fraction of girls ,  with the fraction of boys.  

=\frac{2}{6} +\frac{3}{10}

=\frac{(2*10) +(6*3)}{6*10} =\\ \frac{20+18}{60}

=\frac{38}{60}

=\frac{19}{30}

This means that  from 30 scouts ,  19 are dancing.  

5 0
3 years ago
Kyra has a rock collection when she puts her rocks into 2 equal piles there are no rocks left over when she puts her rocks into
jeyben [28]
Kyra has 12 rocks in her rock collection.
6 0
3 years ago
Read 2 more answers
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