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2 years ago

Help will mark Brainliest

Mathematics

2 answers:

yarga [219]2 years ago

5 0

Answer:

C. is the correct answer

Step-by-step explanation:

A. is incorrect because the sequence does not start with 15

B. is incorrect because the pattern increases by 5, not multiplied by 5

C. is correct because all of the even numbers in the pattern do end in 0

D. is incorrect because even numbers don't end in 5's

Hope this helps!

Wewaii [24]2 years ago

5 0

Answer: "Every even-numbered term in the pattern has a 0 in the evens place"

Step-by-step explanation:

We can compare each statement to the pattern and see which ones don't apply.

The first one is not true. We are adding 5, not having a sum of previous numbers.

The second one is not true, it is adding 5. <em>Not</em> 5 times greater.

An even number is a number ending in 0, 2, 4, 6, or 8. This means

that the third option is correct, giving us our answer.

You might be interested in

According to a 2018 survey by Bankrate, 20% of adults in the United States save nothing for retirement (CNBC website). Suppose t

nalin [4]

Answer:

0.5981 = 59.81% probability that three or less of the selected adults have saved nothing for retirement

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they save nothing for retirement, or they save something. The probability of an adult saving nothing for retirement is independent of any other adult. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

20% of adults in the United States save nothing for retirement (CNBC website).

This means that $p = 0.2$

Suppose that sixteen adults in the United States are selected randomly.

This means that $n = 16$

What is the probability that three or less of the selected adults have saved nothing for retirement?

This is:

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{16,0}.(0.2)^{0}.(0.8)^{16} = 0.0281$

$P(X = 1) = C_{16,1}.(0.2)^{1}.(0.8)^{15} = 0.1126$

$P(X = 2) = C_{16,2}.(0.2)^{2}.(0.8)^{14} = 0.2111$

$P(X = 3) = C_{16,3}.(0.2)^{3}.(0.8)^{13} = 0.2463$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0281 + 0.1126 + 0.2111 + 0.2463 = 0.5981$

0.5981 = 59.81% probability that three or less of the selected adults have saved nothing for retirement

4 0

3 years ago

What is $220 marked up 60%

NNADVOKAT [17]

Answer:

Answer would be $366.70

Step-by-step explanation:

220/60%=366.70

Hope it helps

4 0

4 years ago

Read 2 more answers

Use the stem and leaf plot graph to answer the question.

kogti [31]

<h3>Answer: 13 days</h3>

====================================================

Explanation:

Count the number of leaves marked in green.

Row One: 2 leaves (1 and 8)
Row Two: 3 leaves (3, 6, and 9)
Row Three: 5 leaves (2, 3, 4, 6, 7)
Row Four: 3 leaves (1, 6, and 8)

There are 2+3+5+3 = 13 leaves total. This represents tickets were sold on 13 days.

Each stem and leaf combines to form a different ticket count. For instance, the stem of 1 and leaf of 8 combine to get the value 18. So 18 tickets were sold on that particular day.

7 0

2 years ago

The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or

tigry1 [53]

<u>Answer-</u>

<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>

<u>Solution-</u>

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

$P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}$

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}$

$P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67$

Putting these values,

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%$

5 0

4 years ago

If 1/4c = 1/2d = 4e = 8, what is the value of c + d + e?

Natali5045456 [20]

Answer:c=1/32 d=1/16 e=2

C+d+e=1/32+1/16+2=35/16

Step-by-step explanation:

Solve for c

1/4c =8

C=1/32

1/2d=8

d=1/16

4e=8

e=2

6 0

4 years ago

Help will mark Brainliest​

Help will mark Brainliest