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2 years ago

Help will mark Brainliest

Mathematics

2 answers:

yarga [219]2 years ago

5 0

Answer:

C. is the correct answer

Step-by-step explanation:

A. is incorrect because the sequence does not start with 15

B. is incorrect because the pattern increases by 5, not multiplied by 5

C. is correct because all of the even numbers in the pattern do end in 0

D. is incorrect because even numbers don't end in 5's

Hope this helps!

Wewaii [24]2 years ago

5 0

Answer: "Every even-numbered term in the pattern has a 0 in the evens place"

Step-by-step explanation:

We can compare each statement to the pattern and see which ones don't apply.

The first one is not true. We are adding 5, not having a sum of previous numbers.

The second one is not true, it is adding 5. Not 5 times greater.

An even number is a number ending in 0, 2, 4, 6, or 8. This means

that the third option is correct, giving us our answer.

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What's the scientific notation of 4,890,000? Please show work because I don't really understand how to do this type of math stuf

Oksana_A [137]

The correct answer:
_________________________________________
The number: "4,890,000" ; written in "scientific notation", is:
_________________________________________________
4.89 * 10 ⁶ .
_________________________________________________
To write a number using "scientific notation", one:
_______________________________________________
1) Looks at the entire number, and consider the "string of sequential digits" that are either precede OR any digit or trailing digits of "zero" --- if any exist.
Regardless if any exist, one considers, for a moment, that "string of digits", or "single digit, for that member" as a number, in and of itself. Considering this value as a number, one write the first digit in that number. If there are more than one digit in this "number", one writes a decimal place, and then writes ALL THE DIGITS THAT FOLLOW (if there are any), in sequential order, unit the last non-zero integer is reached. Then, one writes a multiplication sign, and then the number 10 (with an appropriate assigned to the "10", which may be: "1", or a "negative number", or a positive number. To find out the correct number to write, one refers to the ORIGINAL NUMBER; then one looks at what one has written down—and where the decimal point has been written at the number written down. One matches this "decimal point" place to the ORIGINAL number, and then counts the FULL NUMBER OF TENS PLACES to the right, or left, until the ENTIRE number is complete (this would include any "trailing zeros" to the right; OR to the left; but not BOTH. If to the left, one would count UP TO AND INCLUDING the decimal point, but NOT the number "0" that is BEFORE the decimal point. If to the left, the exponent would be a "negative number"; then number of spaces to the LEFT. If to the right, the exponent would be the number of spaces to the RIGHT (including the trailing zeros).
_______________________________
So, for this problem.
_______________________
4.89 * 10⁶ . (That is, 4.89* 10^6 ; because we have the whole number, "4"; then we write the "decimal point". Then we write the sequential digits: "89";
and then: we write:
______________________________
" * 10⁶ " ;
_________________________________
since, after the number "4", we count the 8, then the 9, (which is already TWO (2) places, then all the remaining digits (the remaining FOUR (4) zeros), until the end of the number is reached.
_____________________________________________
Additional note: As a matter of technicality: Consider the following:
__________________________________________
How would we write: "49" ; in scientific notation?
__________________________________________
Answer: In reality, we probably would not write such a small number in scientific notation, but we could if we wanted. The answer would be:
__________________________________________
4.9 * 10¹ .
________________________________________
How would we write: "-49" ; in scientific notation?
_________________________________________________
Answer: Again, in reality we probably wouldn't, because it wouldn't be practical. But the answer is: -4.9 * 10¹ .
_______________________________________________
What is: "0.49" in scientific notation? Answer: 4.9 * 10⁻¹
________________________________________________
Similar to our problem:
_________________________
What is: "0.0000489" in scientific notation?
______________________________________
Answer: 4.89 * 10⁻⁵ (that is, 4.89 * 10^(-5) ). Since we write down the "whole number integer, plus a decimal, then we would count the number of spaces BACK FROM (in this case) the decimal.
______________________________________
What about "0.0000489002" in scientific notation?
________________________________________
Answer: 4.89002 * 10⁻⁵ (that is: 4.89002 * 10^(-5) ).
________________________________________________
What about: 0.0004890000 ?
______________________________
Answer: Though often prone to debate by some, we would still be on the safe side and write as:
_________________________________
4.890000 * 10 ⁻⁴ .
____________________________________
How to write: "5" in scientific notation? Answer: 5 * 10⁰ .
______________________________________________
(since anything to the "0th" power = 1 ;
and as such, 5 = 5 * 10⁰ = 5 * 1 = 5).
__________________________________________________
Hope that this lengthy explanation is of help!

3 0

3 years ago

Help me with my homework

kogti [31]

Answer:

That is right

Step-by-step explanation:

3 0

3 years ago

Use the place values of 35 to fill in the blanks in parentheses.Then, give the value of 2 x 35.(a) 2 x 35 = (2 x D)- (DХа 6?(b)

jonny [76]

In 35, 3 is in the tens place and 5 is in the ones place, that is,

place value of 3: 30

place value of 5: 5

This means that 35 can be expressed as 30 + 5.

Substituting 35 = 30 + 5 into the multiplication given, we get:

$\begin{gathered} 2\cdot35=2\cdot(30+5) \\ \text{Distributing the multiplication over the addition:} \\ 2\cdot35=(2\cdot30)+(2\cdot5) \\ \text{ Solving each multiplication on the right} \\ 2\cdot35=60+10 \\ 2\cdot35=70 \end{gathered}$

8 0

1 year ago

Mason gave the waiter a $14.58 tip, which was 15 percent of the dinner bill. What was the amount of the dinner bill before he ad

Black_prince [1.1K]

C. You take the tip amount devided by 15%. Thats 0.15. You the get the answer 97.20

6 0

3 years ago

Read 2 more answers

When I sit and watch my students take exams, I often think to myself "I wonder if students with bright calculators are impacted

hodyreva [135]

Answer:

There is a difference between the two means.

Step-by-step explanation:

The hypothesis can be defined as:

H₀: The mean exam scores of my SAT 215 students with colorful calculators are same as the mean scores of my STA 215 students with plain black calculators, i.e. μ₁ - μ₂ = 0.

Hₐ: The mean exam scores of my SAT 215 students with colorful calculators are different than the mean scores of my STA 215 students with plain black calculators, i.e. μ₁ - μ₂ ≠ 0.

Assume that the significance level of the test is, α = 0.05. Also assuming that the population variances are equal.

The decision rule:

A 95% confidence interval for mean difference can be used to determine the result of the hypothesis test. If the 95% confidence interval contains the null hypothesis value, i.e. 0 then the null hypothesis will not be rejected.

The 95% confidence interval for mean difference is:

$CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\times S_{p}\times \sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}$

Compute the pooled standard deviation as follows:

$S_{p}=\sqrt{\frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}} {n_{1}+n_{2}-2}}}=\sqrt{\frac{(49-1)(4.7)^{2}+(38-1)(5.7)^{2}}{49+38-2}}=5.16$

The critical value of t is:

$t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.05/2, (49+38-2)}=t_{0.025, 85}=1.984$

*Use a t-table.

Compute the 95% confidence interval for mean difference as follows:

$CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\times S_{p}\times \sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}$

$=(84-87)\pm 1.984\times 5.16\times \sqrt{\frac{1}{49}+\frac{1}{38}}$

$=-3\pm 2.133\\=(-5.133, -0.867)\\\approx(-5.13, -0.87)$

The 95% confidence interval for mean difference is (-5.13, -0.87).

The confidence interval does not contains the value 0. This implies that the null hypothesis will be rejected at 5% level of significance.

Hence, concluding that the mean exam scores of my STA 215 students with colorful calculators are different than the mean scores of my STA 215 students with plain black calculators.

7 0

4 years ago

Help will mark Brainliest​

Help will mark Brainliest