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lakkis [162]
3 years ago
10

Calculate the energy released by the electron-capture decay of 5727co2757co. Consider only the energy of the nuclei (ignore the

energy of the surrounding electrons). The following masses are given:
Chemistry
1 answer:
Mice21 [21]3 years ago
4 0

The energy released by the electron-capture decay is 0.835 MeV.

<h3>What is electron capture?</h3>

Electron capture is a process of electron of low energy orbital are captured by the nucleus.

Δm = m2 - m1

Δm = 56.936296 u - 56.935399 u

Δm = 0.000897‬ u

The energy released by the electron-capture decay

E = Δmc²

( 0.000897‬ u) c² ( 931. 5 MeV /c²/ 1 u)= 0.8355555 MeV

Thus, the energy released by the electron-capture decay is 0.835 MeV.

Learn more about electron capture

brainly.com/question/17215285

#SPJ4

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