Assume that a recent study found that a popular soft drink could destroy the bonds of organic molecules. In a newspaper article
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The two resonating structures of Carbon Monoxide are shown below.
The movement of electrons are shown by arrow.
Structure A:
In structure a A the formal charges of Carbon and Oxygen are zero. As Formal Charge is calculated as,
= # of valence electron - electrons in lone pairs + 1/2 bonding electrons electrons
For C:
= 4 - 2 + 4/2
= 4- 4
= 0
For O:
= 6 - 4 + 4/2
= 6- 6
= 0
Structure B:
Formal Charge on C:
= 4 - 2 + 6/2
= 4- 5
= -1
Formal Charge on O:
= 6 - 2 + 6/2
= 6 - 5
= +1
The movement of electrons are shown by arrow.
Structure A:
In structure a A the formal charges of Carbon and Oxygen are zero. As Formal Charge is calculated as,
= # of valence electron - electrons in lone pairs + 1/2 bonding electrons electrons
For C:
= 4 - 2 + 4/2
= 4- 4
= 0
For O:
= 6 - 4 + 4/2
= 6- 6
= 0
Structure B:
Formal Charge on C:
= 4 - 2 + 6/2
= 4- 5
= -1
Formal Charge on O:
= 6 - 2 + 6/2
= 6 - 5
= +1