When electrons are added to the outermost shell of a carbon atom, it forms an anion.
Answer:
Explanation:
a )
m = m₀
m is mass after time t . original mass is m₀ , λ is disintegration constant
λ = .693 / half life
= .693 / 1590
= .0004358
m = m₀
b )
m = 50 x
= 40.21 mg .
c )
40 = 50
.8 =
= 1.25
.0004358 t = .22314
t = 512 years .
I believe it is "empirical formula"
Answer:
33.33% = 33%
Explanation:
MgCO3(s) + 2HCl (aq) --> MgCl2(aq) + H20(l) + CO2(g)
1 mole of MCO3 will produce → 1 mole of CO2
We need to get the number of mole of CO2:
and when we have 0.22 g of CO2, so number of mole = mass / molar mass
Moles = 0.22 g / 44 g/mol = 0.005 mole
Moles of Mg = moles of CO2 = 0.005 mole
Mass of Mg = moles * molar mass
= 0.005 * 84 /mol = 0.42 g
Percent of MgCO3 by mass of Mg = 0.42 g / 1.26 * 100
=33.33 %
It would be an atom. Hope this helps! :)