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krek1111 [17]
1 year ago
13

Which set of three angles could represent the interior angles of a triangle?

Mathematics
1 answer:
matrenka [14]1 year ago
8 0

Answer:

See below

Step-by-step explanation:

The three numbers in the set have to sum to 180 degrees

If the first choice is  19 70 91    that would be it

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What is the value of x in the equation 5x+ 3 = 4x?<br> A.-3<br> B.- 1/3<br> C.1/3<br> D.3
Elina [12.6K]

Answer:

-3

Step-by-step explanation:

5•-3=-15

4•-3=-12

-15+3=-12

7 0
2 years ago
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The length of a rectangle is 4 inches longer than it is wide. If the area is 60 square inches, what are the dimensions of the re
Ainat [17]

Step-by-step explanation:

akajahsjallamamsjskdkldd

5 0
3 years ago
Tisha and her academic team are working to go to state finals. They must have a certain number of points to advance. They have h
kolbaska11 [484]

Answer:

b=\frac{T-a-c-d}{3}

b = (T - a - c - d) / 3

Step-by-step explanation:

Let T be the total number of points required to advance.

a, c and d are points scored in the local matches, and b is the number of points scored in the district match. If b is worth 3 times as much as the other matches, the total number of points is given by:

T=a+c+d+3b

Isolate b in order to find out how many points they need in the district match:

T=a+c+d+3b\\3b=T-a-c-d\\b=\frac{T-a-c-d}{3}

They need to score (T - a - c - d)/3, in the district match in order to win.

4 0
2 years ago
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
Lauren says the two expressions 3x+4(2x+5) and 6x +5x+5 are equivalent
Allisa [31]

Answer:

so, lauren isn't correct

Step-by-step explanation:

3x + 4 (2x + 5) = 6x + 5x + 5

3x + 8x + 20 = 11x + 5

11x + 20 ≠ 11x + 5

8 0
1 year ago
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