Answer:
Do the data from this shipment indicate statistical control: No
Step-by-step explanation:
Calculating the mean of the sample, we have;
Mean (x-bar) = sum of individual sample/number of sample
= (0+0+0+0.004+0.008+0.020+0.004+0+0+0.008)/10
= 0.044/10
= 0.0044
Calculating the lower control limit (LCL) using the formula;
LCL= (x-bar) - 3*√(x-bar(1-x-bar))/n
= 0.0044 - 3*√(0.0044(1-0.0044))
= 0.0044- (3*0.0042)
= 0.0044 - 0.01256
= -0.00816 ∠ 0
Calculating the upper control limit (UCL) using the formula;
UCL = (x-bar) + 3*√(x-bar(1-x-bar))/n
= 0.0044 + 3*√(0.0044(1-0.0044))
= 0.0044+ (3*0.0042)
= 0.0044 + 0.01256
=0.01696∠ 0
Do the data from this shipment indicate statistical control: No
Since the value 0.02 from the 6th shipment is greater than the upper control limit (0.01696), we can conclude that the data from this shipment do not indicate statistical control.
Answer:The satellite travels for 25600km
Step-by-step explanation:
Answer:
Oka
Step-by-step explanation:
Subtract or multiple
Answer:
Answer B
Step-by-step explanation:
Write out f(x) and g(x) in a column; we will subtract g(x) from f(x):
f(x) = x^2 - 9 or f(x) = x^2 - 9
-g(x) = -(2 - x) or -g(x) = +x -2
---------------------------------
f(x) - g(x) = x^2 + x - 11 (Answer B)
Answer:
it would be 1 million, ( 1,000,000 )
Step-by-step explanation:
1.) look to the right of the nine , (7)
2.) 7 is greater than five therefore rounding it up to 1,000,000
