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2 years ago

How to find the area of a trapezium

Mathematics

2 answers:

Scorpion4ik [409]2 years ago

5 0

The formula is shown in the picture :)

i hope you have a lovely rest of your day!

brilliants [131]2 years ago

5 0

I studied this in physics so i don't know if this will work for you in maths.

Step-by-step explanation:

area of all the shapes i.e.

= (area of rect) + (area of triangle)

= (L x W) + (1/2 (base)(height))

put ur answers and you will get it.

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Please help..thank you

iVinArrow [24]

Answer:

Step-by-step explanation:

To shift down:

F(x)-b

To shift up:

F(x)+b

To shift right:

F(x-b)

To shift left:

F(x+b)

7 0

3 years ago

Read 2 more answers

5x +6y = 20 (1)

slega [8]

(2) + (2)

=> 8x - 6y = -46 ———(3)

(1) + (3)

=> 5x + 6y + (8x - 6y) = 20 - 46

=> 13x + (6-6)y = -26

=> 13x + 0y = -26

=> 13x = -26

=> x = -26/13

=> x = -2

=> 5(-2) + 6y = 20

=> 6y = 20 + 10

=> 6y = 30

=> y = 5

x = -2, y = 5 => C

4 0

2 years ago

Read 2 more answers

Graph f(x)=2ˣ−1 and g(x)=−x+5 on the same coordinate plane.

Evgesh-ka [11]

Graph attached

Solution is (2,3)

3 0

2 years ago

Assume that the probability of a defective computer component is 0.02. Components arerandomly selected. Find the probability tha

solmaris [256]

Answer:

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.

Step-by-step explanation:

Assume that the probability of a defective computer component is 0.02. Components are randomly selected. Find the probability that the first defect is caused by the seventh component tested.

First six not defective, each with 0.98 probability.

7th defective, with 0.02 probability. So

$p = (0.98)^6*0.02 = 0.0177$

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.

Find the expected number and variance of the number of components tested before a defective component is found.

Inverse binomial distribution, with $p = 0.02$

Expected number before 1 defective(n = 1). So

$E = \frac{n}{p} = \frac{1}{0.02} = 50$

Variance is:

$V = \frac{np}{(1-p)^2} = \frac{0.02}{(1-0.02)^2} = 0.0208$

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.

5 0

3 years ago

Please help no troll im really confused i'm offering 20 points

MatroZZZ [7]

Answer:

4) choice 1) 14.7 cm

5) choice 2) 14.8 cm

Step-by-step explanation:

4) 10^2 + 10^2 + 4^2 = 216

sq rt 216 = 14.7

5) 14^2 + 3^2 + 4^2 = 221

sq rt 221 = 14.86

3 0

3 years ago

How to find the area of a trapezium​

How to find the area of a trapezium