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2 years ago

If X is a random variable denoting number of defective items, which discrete probability distribution is appropriate

1 answer:

6 0

Considering that for each item, there are only two possible outcomes, and the probability of an item being defective is independent of any other item, the binomial distribution is appropriate.

<h3>What is the binomial probability distribution?</h3>

It is the probability of <u>exactly x successes on n repeated trials, with p probability</u> of a success on each trial.

More can be learned about the binomial distribution at brainly.com/question/24863377

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In the diagram below, AABC-ADEC. What is the value of x?

Marina86 [1]

Answer:

Step-by-step explanation:

Number 4

7 0

3 years ago

Which series of transformations will not map figure H onto itself

7nadin3 [17]

Answer:

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation $(x+0,y-2)$ will map vertices of the square into points

$(2,1)\rightarrow (2,-1);$
$(1,2)\rightarrow (1,0);$
$(2,3)\rightarrow (2,1);$
$(3,2)\rightarrow (3,0).$

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

$(2,-1)\rightarrow (2,3);$
$(1,0)\rightarrow (1,2);$
$(2,1)\rightarrow (2,1);$
$(3,0)\rightarrow (3,2)$

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation $(x+2,y-0)$ will map vertices of the square into points

$(2,1)\rightarrow (4,1);$
$(1,2)\rightarrow (3,2);$
$(2,3)\rightarrow (4,3);$
$(3,2)\rightarrow (5,2).$

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

$(4,1)\rightarrow (2,1);$
$(3,2)\rightarrow (3,2);$
$(4,3)\rightarrow (2,3);$
$(5,2)\rightarrow (1,2)$

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation $(x+3,y+3)$ will map vertices of the square into points

$(2,1)\rightarrow (5,4);$
$(1,2)\rightarrow (4,5);$
$(2,3)\rightarrow (5,6);$
$(3,2)\rightarrow (6,5).$

2nd transformation = reflection over y = -x + 7 will map vertices into points

$(5,4)\rightarrow (3,2);$
$(4,5)\rightarrow (2,3);$
$(5,6)\rightarrow (1,2);$
$(6,5)\rightarrow (2,1)$

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation $(x-3,y-3)$ will map vertices of the square into points

$(2,1)\rightarrow (-1,-2);$
$(1,2)\rightarrow (-2,-1);$
$(2,3)\rightarrow (-1,0);$
$(3,2)\rightarrow (0,-1).$

2nd transformation = reflection over y = -x + 2 will map vertices into points

$(-1,-2)\rightarrow (4,3);$
$(-2,-1)\rightarrow (3,4);$
$(-1,0)\rightarrow (2,3);$
$(0,-1)\rightarrow (3,2)$

These points are not the vertices of the initial square.

5 0

3 years ago

Twenty-one fish are swimming in an aquarium. Eleven are removed, leaving 10 fish. Which number is the additive inverse of the nu

agasfer [191]

The additive inverse: The usage of addition with a negative number.

The original equation is 21 - 11 = 10

To use the additive inverse, change it so that there is an addition sign.

21 + (-11) = 10

B) -11 is your answer

hope this helps

7 0

3 years ago

Read 2 more answers

What is the answer to this question 8 1/2- 7 1/4

zysi [14]

1 1/4 because you must make improper fractions

4 0

3 years ago

Read 2 more answers

A plumber charges $52.50 per hour plus a $75.00 service charge. Your father's firm hired him to fix some leaky pipes.

Setler79 [48]

Cost as a function of hours is:

c(h)=52.5h+75

4 0

4 years ago