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3 years ago

Please Help URGENT!!

Mathematics

2 answers:

Zinaida [17]3 years ago

5 0

To find y you add 79 and 37 =116

180 - 116 =y
y= 64

AlekseyPX3 years ago

3 0

Y + 79 + 37 = 180
y + 116 = 180
y = 64

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There are 96 girls and 72 boys who want to participate in 6th grade intramurals.

Gekata [30.6K]

Answer:

i) 24

ii) 4 girls, 3 boys

Step-by-step explanation:

The GCF is 24

96= 24*4

72= 24*3

I hope this helps!

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3 years ago

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stealth61 [152]

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3 0

2 years ago

Find the components of the vertical force Bold Upper FFequals=left angle 0 comma negative 10 right angle0,−10 in the directions

quester [9]

Solution :

Let $v_0$ be the unit vector in the direction parallel to the plane and let $F_1$ be the component of F in the direction of $v_0$ and $F_2$ be the component normal to $v_0$ .

Since, $|v_0| = 1,$

$(v_0)_x=\cos 60^\circ= \frac{1}{2}$

$(v_0)_y=\sin 60^\circ= \frac{\sqrt 3}{2}$

Therefore, $v_0 = \left$

From figure,

$|F_1|= |F| \cos 30^\circ = 10 \times \frac{\sqrt 3}{2} = 5 \sqrt3$

We know that the direction of $F_1$ is opposite of the direction of $v_0$ , so we have

$F_1 = -5\sqrt3 v_0$

$=-5\sqrt3 \left$

$= \left$

The unit vector in the direction normal to the plane, $v_1$ has components :

$(v_1)_x= \cos 30^\circ = \frac{\sqrt3}{2}$

$(v_1)_y= -\sin 30^\circ =- \frac{1}{2}$

Therefore, $v_1=\left< \frac{\sqrt3}{2}, -\frac{1}{2} \right>$

From figure,

$|F_2 | = |F| \sin 30^\circ = 10 \times \frac{1}{2} = 5$

∴ $F_2 = 5v_1 = 5 \left< \frac{\sqrt3}{2}, - \frac{1}{2} \right>$

$=\left$

Therefore,

$F_1+F_2 = \left< -\frac{5\sqrt3}{2}, -\frac{15}{2} \right> + \left< \frac{5 \sqrt3}{2}, -\frac{5}{2} \right>$

$= = F$

3 0

2 years ago

Julia is allowed to watch no more than 5 hours of television a week. So far this week, she has watched 1.5 hours. Write and solv

Leona [35]

The inequality is used to solve how many hours of television Julia can still watch this week is $x + 1.5 \leq 5$

The remaining hours of TV Julia can watch this week can be expressed is 3.5 hours

<h3>Solution:</h3>

Given that Julia is allowed to watch no more than 5 hours of television a week

So far this week, she has watched 1.5 hours

To find: number of hours Julia can still watch this week

Let "x" be the number of hours Julia can still watch television this week

"no more than 5" means less than or equal to 5 ( ≤ 5 )

Juila has already watched 1.5 hours. So we can add 1.5 hours and number of hours Julia can still watch television this week which is less than or equal to 5 hours

number of hours Julia can still watch television this week + already watched ≤ Total hours Juila can watch

$x + 1.5 \leq5$