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Zolol [24]
3 years ago
12

Which is a possible turning point for the continuous

Mathematics
1 answer:
katrin2010 [14]3 years ago
5 0
Choice B: (-2,-1) is the answer
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Sharif's portfolio generated returns of 12 percent, 15 percent, −15 percent, 19 percent, and −12 percent over five years. What w
qwelly [4]

Answer:

3.8 percent

Step-by-step explanation:

To find his average return over n years, we sum all of his returns, and divide by n.

In this problem:

5 years.

The sum is (12 + 15 - 15 + 19 - 12) = 19

19/5 = 3.8

So the correct answer is:

3.8 percent

8 0
4 years ago
PLEASE HELP DUE IN AN HOUR NO LINKS PLEASE. ​
Korolek [52]

Answer:

y = 3/2  when x = 15

Step-by-step explanation:

y = k / √1+x  

2 = k / √1+8 = k/3  

k = 6  

y' = 6 / √1+15 = 6/4 = 3/2

5 0
3 years ago
What is 12% of 75? =)))
ankoles [38]

Answer:

Hope this helps!

Step-by-step explanation:

12% of 75 would be 9

5 0
3 years ago
Read 2 more answers
Suppose A and B represent two different school populations where A > B and A and B must be greater than 0. Which of the follo
Ulleksa [173]
We can reject the last one: subtracting a non-zero value will result in a smaller value.

So now we have:

<span>2(A + B)
(A + B)2
A2 + B2

If all of them are mulptiplications, then they are all equivalent!

I mean by this, if what you meant is this:

</span>
<span>2*(A + B)
(A + B)*2
A*2 + B*2

If there is no sign, then the multiplication sign is implicit,


and all of these expressions say exactly the same: two of A and two of B.
</span>
6 0
3 years ago
(1−√(5))×(2−√(5)) <br><img src="https://tex.z-dn.net/?f=%281%20%2B%204%20%5Csqrt%7B10%7D%20%29%282%20-%20%20%5Csqrt%7B10%7D%20%2
Leviafan [203]
To simplify these expressions, you can either use a calculator (which I'm assuming your teacher doesn't want you to do) or FOIL (distribute).

The first one would be:

(1- \sqrt{5}) (2- \sqrt{5}) \newline =(1)(2)+(1)(- \sqrt{5} )+(- \sqrt{5})(2)+(- \sqrt{5})(- \sqrt{5}) \newline =2- \sqrt{5}-2 \sqrt{5}+5 \newline =7-3 \sqrt{5}

The second one would be:

(1+4 \sqrt{10})( 2- \sqrt{10}) \newline =(1)(2)+(1)(- \sqrt{10})+(4 \sqrt{10} )(2)  +(4 \sqrt{10})(- \sqrt{10}) \newline =2-\sqrt{10}+8 \sqrt{10} -40 \newline =-38+7 \sqrt{10}
3 0
3 years ago
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