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densk [106]
3 years ago
6

which of the following best describes the relationship between (x+1) and the polynomial -3x^3-2x^2+1 a) (x+1) is a factor b) (x+

1) is not a factor c) it is impossible to tell whether (x+1) is a factor
Mathematics
2 answers:
aivan3 [116]3 years ago
5 0

Answer:

I will solve this problem by factor theorem.

If , (x+1) is a factor of the polynomial , f(x)=-3 x^3-2 x^2 +1 then ,if we substitute,x= -1 in f(x), then, f(-1)=0.

Now,

f(-1)= -3\times (-1)^3-2 \times (-1)^2+1\\\\ f(-1)=-3 \times (-1)-2 \times 1+1\\\\ f(-1)=3 -2+1\\\\ f(-1)=2

As, f(-1)≠ 0

Option B: (x+1) is not a factor of the polynomial , f(x)=-3 x^3-2 x^2 +1.

zheka24 [161]3 years ago
4 0
Hello,

3x^3+2x²-1=(x-1)(3x²-x+1)+2
remainder is 2
(x+1) is not a factor of 3x^3+2x²-1 nor of -(3x^3+2x²-1)= -3x²-2x²+1.

Answer B
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1. Find the area of the polygon
zhannawk [14.2K]

Answer:

1. A = 40 units²

2. A = 72 units²

3. B) 45

Step-by-step explanation:

1.  This shape comprises 4 congruent triangles with base of 5 units and height of 5 units.

Area of a triangle = 1/2 x base x height

Therefore, area of polygon = 4(1/2 x 5 x 4)

                                             = 40 units²

2.  This shape comprises two pairs of congruent triangles.

Area of a triangle = 1/2 x base x height

Therefore, area of polygon = 2(1/2 x 2 x 6) + 2(1/2 x 10 x 6)

                                             = 72 units²

3.  Count the number of shaded squares:

9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 45 units²

7 0
2 years ago
Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t
Svet_ta [14]

Answer:

[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}

[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}

[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]

Finally, the third vector of basis E is e3(t)=t^{2}

T[e3(t)]=T(t^{2})

in the equation : a2 = 1

T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}

Then

[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]

And that is the third column of [T]EE

Let's write our matrix

[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

X=\left[\begin{array}{c}1&0&0\\\end{array}\right]

AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]

Applying the coordinates 2,6 and -2 to the basis E we obtain

2+6t-2t^{2}

That was the original result of T[e1(t)]

8 0
3 years ago
A sample of 11001100 computer chips revealed that 62b% of the chips fail in the first 10001000 hours of their use. The company's
STALIN [3.7K]

Answer:

Rule

If;

P-value > significance level --- accept Null hypothesis

P-value < significance level --- reject Null hypothesis

Z score > Z(at 90% confidence interval) ---- reject Null hypothesis

Z score < Z(at 90% confidence interval) ------ accept Null hypothesis

Null hypothesis: H0 = 0.60

Alternative hypothesis: Ha <> 0.62

z score = 1.35

P value = P(Z<-1.35) + P(Z>1.35) = 0.0885 + 0.0885= 0.177

Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = 1.35) falls with the region bounded by Z at 0.1 significance level. And also the two-tailed hypothesis P-value is 0.177 which is greater than 0.1. Then we can conclude that we don't have enough evidence to FAIL or reject the null hypothesis, and we can say that at 0.10 significance level the null hypothesis is valid.

Question; A sample of 1100 computer chips revealed that 62% of the chips fail in the first 1000 hours of their use. The company's promotional literature states that 60% of the chips fail in the first 1000 hours of their use. The quality control manager wants to test the claim that the actual percentage that fail is different from the stated percentage. Determine the decision rule for rejecting the null hypothesis, H0, at the 0.10 level.

Step-by-step explanation:

Given;

n=1100 represent the random sample taken

Null hypothesis: H0 = 0.60

Alternative hypothesis: Ha <> 0.62

Test statistic z score can be calculated with the formula below;

z = (p^−po)/√{po(1−po)/n}

Where,

z= Test statistics

n = Sample size = 1100

po = Null hypothesized value = 0.60

p^ = Observed proportion = 0.62

Substituting the values we have

z = (0.62-0.60)/√{0.60(1-0.60)/1100}

z = 1.354

z = 1.35

To determine the p value (test statistic) at 0.01 significance level, using a two tailed hypothesis.

P value = P(Z<-1.35) + P(Z>1.35) = 0.0885 + 0.0885= 0.177

Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = 1.35) falls with the region bounded by Z at 0.1 significance level. And also the two-tailed hypothesis P-value is 0.177 which is greater than 0.1. Then we can conclude that we don't have enough evidence to FAIL or reject the null hypothesis, and we can say that at 0.10 significance level the null hypothesis is valid.

3 0
3 years ago
A diver descended at a constant rate of 16.05 feet every 3 minutes. Which of the following is true?
bekas [8.4K]
<span>Determine the lower limit of the 95% interval for the true mean weight. ... A diver descended at a constant rate of 12.24 feet every 3 minutes. .... weight of 16.05 ounces. at the 5% level of significance can we conclude that ...</span><span>

</span>
5 0
3 years ago
Use the limit theorem and the properties of limits to find the limit.<br> Picture provided below
sashaice [31]

Answer:

b. 1/2

Step-by-step explanation:

lim        (x -3)(x +2)

x-->-∞    ---------------

              2x^2 + x +1

= lim        (x^2 -3x +2x - 6)

x-->-∞    -----------------------

              2x^2 + x +1

= lim        (x^2 -x - 6)

x-->-∞    -----------------------

              2x^2 + x +1

When we plug in x = -∞, we get indeterminate form.

Now we have to use the L'hospital rule.

d/dx (x^2 - x - 6) = 2x -1

d/dx (2x^2 + x + 1) = 4x + 1

Now apply the limit

lim            (2x - 1) / (4x + 1)

x--->-∞

Here we have to degree of the numerator and the denominator of the same. In this case, if x --> -∞, we get the result as the coefficient of the leading term as the result.

According to the rule, we get

= 2/4

Which can simplified as 1/2

The answer is 1/2

Hope this will helpful.

Thank you.

3 0
3 years ago
Read 2 more answers
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