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bonufazy [111]
3 years ago
7

I hope to better understand these math questions, could you help me?

Mathematics
1 answer:
mart [117]3 years ago
7 0
Answer is SSA  (first choice)

cause LE perpendicular to BU so LEB = LEU = 90

hope it helps
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Find two numbers whos diffrence is 16 and the product is 720
antiseptic1488 [7]

Answer:

the numbers who's difference is 16 and the product is 720 is

36 &20

Explanation:

to finding numbers you have to express the equation in a quadratic equation then Factor it.

since the two numbers have a difference of 16 you can say that the first number is x and the second number is x -16 then their product is 720.

x(x-16)=720

x²-16x=720

x²-16x-720=0

(x-36)(x+20)

there are two possible value of x but since you are looking for the positive value of x, choose the positive value of x the first number is 20.

To find the second number

x-16=20

x=20+16

x=36

the second number is 36

<u>Now </u><u>to </u><u>check</u>

<u>3</u><u>6</u><u>-</u><u>2</u><u>0</u><u>=</u><u>1</u><u>6</u>

<u>2</u><u>0</u><u>*</u><u>3</u><u>6</u><u>=</u><u>7</u><u>2</u><u>0</u>

8 0
3 years ago
PLEASE HELP, ITS TIMED HURRY &gt;&gt;&gt;&gt;
tresset_1 [31]

Answer:2

Step-by-step explanation:

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3 0
3 years ago
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Write six hundred fifty-eight and twenty-nine thousandths in standard form​
Pepsi [2]

Answer:

658.029

Step-by-step explanation:

hope this helps  (´▽`ʃ♡ƪ)

7 0
2 years ago
Read 2 more answers
IF SOMEONE COULD HELP WITH THIS IT WOULD BE MUCH APPRECIATED!
julsineya [31]

Answer:

48 Units

Step-by-step explanation:

Use the Pythagorean theorem to make two right triangles.

Ex= Base is cut in half to make two 9 unit bases

Then count the units from the half point.

Ex= 12 units long

Then use Pythagorean theorem to find one side of the 9-12 right triangle

Ex= 9^2+12^2=c^2

After finding that c=15 units, add all the sides back together

Ex= 18+15+15=48

4 0
3 years ago
Find the solution to the initial value problem (1 + x^{5}) y' + 5 x^{4} y = 5 x^{8}
natali 33 [55]
(1+x^5)y'+5x^4y=5x^8
\bigg((1+x^5)y\bigg)'=5x^8
(1+x^5)y=5\displaystyle\int x^8\,\mathrm dx
(1+x^5)y=\dfrac59x^9+C
y=\dfrac{5x^9+C}{9(1+x^5)}
8 0
3 years ago
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