Ask question

Ask question

All categories

2 years ago

14

Find the mean of the following data set. 14,24,35,37,43,35,45,24,29,41,45,

1 answer:

Masja [62]2 years ago

3 0

The mean of the data set is 33.8

You might be interested in

The probability that Scott will win his next tennis match is \frac{3}{5}

blagie [28]

3/5 is the probability that he will win, you must find a fraction which adds to make 100%.

2/5 would be the fraction for his probability to lose.

0.4 or 40%.

6 0

3 years ago

Write the log equation as an exponential equation

Serjik [45]

Answer:

$(z+5)^{(3x+4)} = 9$

Step-by-step explanation:

Tip: When $log_{a} b = c$ , $a^{c} =b$ is also true.

$log_{z+5} (9) = 3x+4$ | <em>Original equation</em>

$(z+5)^{(3x+4)} = 9$ | <em>Use tip</em>

7 0

3 years ago

Read 2 more answers

Sum of $12000 from a financing company for 3 years at 15% per annum. What is the total interest he paid in 3 years

Dahasolnce [82]

So there are many factors to this, but lets assume the basics:

-He made equal payments every month for 36 months

assuming that is true, the answer is $2,975.42

Assuming that is NOT true and he made NO monthly payments at all and at the end paid the entire balance, the interest would be $6,250.50

7 0

3 years ago

Read 2 more answers

Consider the system of differential equations dxdt=−4ydydt=−4x. Convert this system to a second order differential equation in y

koban [17]

$\dfrac{\mathrm dy}{\mathrm dt}=-4x\implies x=-\dfrac14\dfrac{\mathrm dy}{\mathrm dt}\implies\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}$

Substituting this into the other ODE gives

$-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}=-4y\implies y''-16y=0$

Since $x(t)=-\dfrac14y'(t)$ , it follows that $x(0)=-\dfrac14y'(0)=4\implies y'(0)=-16$ . The ODE in $y$ has characteristic equation

$r^2-16=0$

with roots $r=\pm4$ , admitting the characteristic solution

$y_c=C_1e^{4t}+C_2e^{-4t}$

From the initial conditions we get

$y(0)=5\implies 5=C_1+C_2$

$y'(0)=16\implies-16=4C_1-4C_2$

$\implies C_1=\dfrac12,C_2=\dfrac92$

So we have

$\boxed{y(t)=\dfrac12e^{4t}+\dfrac92e^{-4t}}$

Take the derivative and multiply it by -1/4 to get the solution for $x(t)$ :

$-\dfrac14y'(t)=\boxed{x(t)=-\dfrac12e^{4t}+\dfrac92e^{-4t}}$

7 0

3 years ago

sing a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion down the second column.Star

Taya2010 [7]

The answer is 32.51^-3

5 0

3 years ago