Can someone please tell me if I am correct?

Mathematics

1 answer:

Lana71 [14]3 years ago

6 0

You are correct. Good job. The correct answer would be that she should have 16 orange carnations and 8 yellow carnations.

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a father is 27 years older than his son. ten years ago he was twice as old as his son. how old is the father

BlackZzzverrR [31]

Answer:

thus the father is 64 years and son is 37years

Step-by-step explanation:

Let father be X and son be y

X=27+Y...........(I)

X-10=2(Y-10)

putting the value of X from eqn(I)

27+Y-10=2Y-20

Y+17=2Y-20

17+20=2Y-Y

37=y

X=27+Y

X=64

7 0

3 years ago

Enter the inequality of the graph below.

aev [14]

The slope is (8-2)/(0-2)=-3
the y intercept is 8
the equation is y=-3x+8
the area to the left is shaded, and the line is solid, so y $\leq$ -3x+8

4 0

3 years ago

5) Two machines M1, M2 are used to manufacture resistors with a design

Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that $\mu = 1050, \sigma = 100$