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MArishka [77]
3 years ago
7

WORTH 50 POINTSSS

Mathematics
2 answers:
Dahasolnce [82]3 years ago
7 0

The equation of the perpendicular is \boxed{y=- 3x - 7}.

Further explanation:

The linear equation with slope m and intercept c is given as follows.

\boxed{y = mx + c}

The formula for slope of line with points \left( {{x_1},{y_1}} \right) and \left( {{x_2},{y_2}} \right) can be expressed as,

\boxed{m = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}}

Given:

The equation of the line is - x + 3y = 9 and passes through the point is \left( { - 3,2} \right).

Explanation:

The product of the slope of perpendicular line and the slope of line is -1.

\boxed{{m_1} \times {m_2} =  - 1}

Solve the equation - x + 3y = 9.

\begin{aligned}- {\text{ }}x + 3y&= 9\\3y &= 9 + x\\y&= \frac{1}{3}x + \frac{9}{3}\\y&= \frac{1}{3}x+3\\\end{aligned}

The slope of the line is {m_1} = \dfrac{1}{3}.\

The slope of perpendicular line can be obtained as follows,

\begin{aligned}{m_1} \times {m_2}&=- 1\\\frac{1}{3} \times {m_2}&= - 1\\{m_2}&= - 3\\\end{aligned}

The passes through the point is \left( { - 3,2} \right).

Substitute -3 for x, 2 for y and -3 for m in equation y = mx + c.

\begin{aligned}2&=- 3\left({- 3}\right)+ c\\2&= 9 + c\\ 2 - 9&= c\\- 7&= c\\\end{aligned}

The equation of the perpendicular is \boxed{y =- 3x - 7}.

Learn more:

1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.

2. Learn more about equation of circle brainly.com/question/1506955.

3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Linear equation

Keywords: equation of a line, perpendicular, -x+3y=9, passes through point, (-3,2) numbers, slope, slope intercept, inequality, equation, linear inequality, shaded region, y-intercept, graph, representation, origin.

SpyIntel [72]3 years ago
4 0

We know that if two lines are Perpendicular then Product of Slopes of both of these Perpendicular lines should be Equal to -1

Given : Equation of 1st Perpendicular line is -x + 3y = 9

This can be written as :

3y = x + 9

y = x/3 + 3

Comparing with standard form : y = mx + c

we can notice that slope of 1st Perpendicular line = 1/3

Slope of 1st Line × Slope of 2nd line = -1

1/3 × Slope of 2nd line = -1

Slope of 2nd line = -3

We know that the form of line passing through point (x₀ , y₀) and having slope m is :

y - y₀ = m(x - x₀)

Here the 2nd Perpendicular line passes through the point (-3 , 2)

x₀ = -3 and y₀ = 2 and we found m = -3

⇒ y - 2 = -3(x + 3)

⇒ -3x - 9 = y - 2

⇒ -3x - y = 7

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