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natka813 [3]
3 years ago
15

Give an example from your classroom of three collinear points

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
4 0
Chess board? , the board if there is like a line with points that has points on the same line. 
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Someone explain it please
Alina [70]

9514 1404 393

Answer:

  ∠A = 44°

Step-by-step explanation:

In order to find the measure of angle A, you need to know the value of the variable x. This means you need some relation that you can solve to find x.

Happily, that relation is "the sum of angles in a triangle is 180°." This means ...

  84° +(x +59)° +(x +51)° = 180°

  (2x + 194)° = 180° . . . collect terms

  2x = -14 . . . . . . . . . . divide by °, and subtract 194

  x = -7 . . . . . . . . . . . .divide by 2

Now, the measure of angle A is ...

  ∠A = (x +51)° = (-7 +51)°

  ∠A = 44°

4 0
3 years ago
If you drive 23 miles south, make a turn and drive 39 miles east, how far are you, in a straight line, from
Rom4ik [11]

Answer:

45.27 miles

Step-by-step explanation:

Pythagorean theorem

23^2 + 39^2 = d ^ 2

d = 45.27 miles

6 0
1 year ago
If g(x)= square root of 3-5x, find the domain of g'(x).
BaLLatris [955]

Answer:

domain: x>3/5

Step-by-step explanation:

First we need to derive our function g(x) to get a new function g'(x)

To do this we will have to apply chain rule because we have an inner and outer functions.

Our G(x) = square root(3-5x)

Chain rule formula states that: d/dx(g(f(x)) = g'(f(x))f'(x)

where d/dx(g(f(x)) = g'(x)

g(x) is the outer function which is x^1/2

f(x) is our inner function which is 3-5x

therefore f'(x)= 1/2x^(-1/2) and f'(x) = -5

g'(f(x)) = -1/2(3-5x)^(-1/2)

Applying chain rule then g'(x) = 1/2 (3-5x)^(-/1/2)*(-5)

But the domain is the values of x where the function g'(x) is not defined

In this case it will be 3-5x > 0, because 3-5x is a denominator and anything divide by zero is infinity/undefined

which gives us x >3/5

5 0
3 years ago
Read 2 more answers
How many terms are in the arithmetic sequence 9, 2, −5, . . . , −187?
Fantom [35]
9, 2, -5... so is going down by 7 each time, meaning the "common difference" is -7.

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=9\\
d=-7\\
a_n=-187
\end{cases}
\\\\\\
-187=9+(n-1)(-7)\implies -187=9-7n+7
\\\\\\
7n=9+7+187\implies 7n=203\implies n=\cfrac{203}{7}\implies \boxed{n=29}
4 0
3 years ago
Please look at the image
Tpy6a [65]

Answer: ok i did :)

Step-by-step explanation: how are you?

6 0
2 years ago
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