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liq [111]
2 years ago
15

Arianna earns a weekly salary of $400 plus a 6.5% commission on sales at a gift shop. How much would she make in a workweek if s

he sold $4800 worth of merchandise?
Mathematics
1 answer:
lilavasa [31]2 years ago
6 0

Answer:

712

Step-by-step explanation:

400+6.5%of 4800

312+400=712

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Dr. Tu must administer emergency medicine to his patient, Mrs. Jones. The
galben [10]

Answer:

168

Step-by-step explanation: You would do 140/100 = 1.4 then multiply 120 by 1.4 which is 168.

3 0
2 years ago
Find the equation for 4x/5=1/3(2x-15)
tia_tia [17]
4x / 5 = 1 / 3 ( 2x - 15 )
4x / 5= ( 2x - 15 ) / 3
4x × 3 = 5 ( 2x - 15 )
12x = 10x - 75
12x - 10x = - 75
2x = - 75
x = - 75 / 2
x = - 37.5
7 0
3 years ago
To decrease an amount by 62%, what single multiplier would you use?
adell [148]
You have to times it by 100 - however much you want to decrease it by so your multiplier would 0.38
5 0
2 years ago
You are dividing 30 tomato plants into equal rows for planting. how many possibilities are there?​
Ierofanga [76]

Answer:

6,5 5,6 3,10 10,3 1,30 30,1 2,15 15,2 = 8 possibilities

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
TDaP is a booster shot that prevents Diphtheria, Tetanus, and Pertussis in adults and adolescents. It should be administered eve
tiny-mole [99]

Answer:

Yes. There is enough evidence to support the claim that the proportion of individuals who caught pertussis and were not up to date on their booster shot is higher than those that were.

P-value = 0.00013.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion of individuals who caught pertussis and were not up to date on their booster shot is higher than those that were.

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0

The significance level is 0.05.

The sample 1 (Group 1), of size n1=145 has a proportion of p1=0.124.

p_1=X_1/n_1=18/145=0.124

The sample 2 (Group 2), of size n2=355 has a proportion of p2=0.037.

p_2=X_2/n_2=13/355=0.037

The difference between proportions is (p1-p2)=0.088.

p_d=p_1-p_2=0.124-0.037=0.088

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{18+13.135}{145+355}=\dfrac{31}{500}=0.062

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.062*0.938}{145}+\dfrac{0.062*0.938}{355}}\\\\\\s_{p1-p2}=\sqrt{0+0}=\sqrt{0.001}=0.024

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.088-0}{0.024}=\dfrac{0.088}{0.024}=3.68

This test is a right-tailed test, so the P-value for this test is calculated as (using a z-table):

\text{P-value}=P(z>3.68)=0.00013

As the P-value (0.00013) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of individuals who caught pertussis and were not up to date on their booster shot is higher than those that were.

8 0
3 years ago
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