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Gwar [14]
2 years ago
13

If a reaction vessel initially contains an N2O4N2O4 concentration of 0. 0550 MM at 500 KK , what are the equilibrium concentrati

ons of N2O4N2O4 and NO2NO2 at 500 KK
Chemistry
1 answer:
ololo11 [35]2 years ago
7 0

The concentration of NO2 is 0.054 M and that of N2O4 is 0.003 M.

<h3>Equilibrium constant</h3>

The equilibrium constant shows the extent to which reactants are converted into products.

We have the reaction;  N2O4⇌2NO2 and Kp = 4.5. Setting up the ICE table, we have;

       N2O4       ⇌     2NO2

I       0. 0550               0

C       -x                        +x

E    0. 0550 - x            x

Given that;

Kp = [NO2]^2/[N2O4]

4.5= (x)^2/0. 0550 - x

4.5(0. 0550 - x) = x^2

0.2475 - 4.5x = x^2

x^2 +  4.5x -  0.2475 = 0

x=0.054 M

The concentration of the required NO2 gas at equilibrium is 0.054 M and that of N2O4 is 0.003 M.

Learn more about equilibrium constant: brainly.com/question/17960050

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