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Gwar [14]
2 years ago
13

If a reaction vessel initially contains an N2O4N2O4 concentration of 0. 0550 MM at 500 KK , what are the equilibrium concentrati

ons of N2O4N2O4 and NO2NO2 at 500 KK
Chemistry
1 answer:
ololo11 [35]2 years ago
7 0

The concentration of NO2 is 0.054 M and that of N2O4 is 0.003 M.

<h3>Equilibrium constant</h3>

The equilibrium constant shows the extent to which reactants are converted into products.

We have the reaction;  N2O4⇌2NO2 and Kp = 4.5. Setting up the ICE table, we have;

       N2O4       ⇌     2NO2

I       0. 0550               0

C       -x                        +x

E    0. 0550 - x            x

Given that;

Kp = [NO2]^2/[N2O4]

4.5= (x)^2/0. 0550 - x

4.5(0. 0550 - x) = x^2

0.2475 - 4.5x = x^2

x^2 +  4.5x -  0.2475 = 0

x=0.054 M

The concentration of the required NO2 gas at equilibrium is 0.054 M and that of N2O4 is 0.003 M.

Learn more about equilibrium constant: brainly.com/question/17960050

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Hello, this question is incomplete. The complete question would be:

"Write the balanced chemical equation for the following reaction.

Solid iron(III) oxide reacts with hydrogen gas to form solid iron and liquid water"

Answer:

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Explanation:

In a chemical reaction, the structure of atoms as chemical elements is unchanged. Atoms in one element do not become atoms in another element. There is also no loss or creation of new atoms. The number of atoms of the reagents must be equal to the number of atoms of the products. When this happens, we say that the chemical equation is balanced.

For this reason, we can state that the balanced chemical reaction where solid iron (III) oxide reacts with hydrogen gas to form solid iron and liquid water would be:

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