Choose whether the statements about oil sands are true or false. The viscosity of bitumen is about 100 times greater than the vi
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<u>Answer:</u> The percent yield of the nitrogen gas is 11.53 %.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
- <u>For NO:</u>
Given mass of NO = 11.5 g
Molar mass of NO = 30 g/mol
Putting values in equation 1, we get:
- <u>For
:</u>
Given mass of = 102.1 g
Molar mass of = 92 g/mol
Putting values in equation 1, we get:
For the given chemical reactions:
......(2)
.......(3)
- <u>Calculating the experimental yield of nitrogen gas:</u>
By Stoichiometry of the reaction 3:
6 moles of NO is produced from 2 moles of
So, 0.383 moles of NO will be produced from = of
By Stoichiometry of the reaction 2:
1 mole of produces 3 moles of nitrogen gas
So, 0.128 moles of will produce =
of nitrogen gas
Now, calculating the experimental yield of nitrogen gas by using equation 1, we get:
Moles of nitrogen gas = 0.384 moles
Molar mass of nitrogen gas = 28 g/mol
Putting values in equation 1, we get:
- <u>Calculating the theoretical yield of nitrogen gas:</u>
By Stoichiometry of the reaction 2:
1 mole of produces 3 moles of nitrogen gas
So, 1.11 moles of will produce =
of nitrogen gas
Now, calculating the theoretical yield of nitrogen gas by using equation 1, we get:
Moles of nitrogen gas = 3.33 moles
Molar mass of nitrogen gas = 28 g/mol
Putting values in equation 1, we get:
- To calculate the percentage yield of nitrogen gas, we use the equation:
Experimental yield of nitrogen gas = 10.75 g
Theoretical yield of nitrogen gas = 93.24 g
Putting values in above equation, we get:
Hence, the percent yield of the nitrogen gas is 11.53 %.