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3 years ago

In the Lewis structure for ICl2–, how many lone pairs of electrons are around the central iodine atom.

Chemistry

1 answer:

Stells [14]3 years ago

3 0

Answer : The number of lone pairs of electrons around the central iodine atom are, 6 electrons

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The representation of valence electrons of an atom by dots around the symbol of an element is said to be the Lewis-dot symbol.

In the representation of Lewis-symbol, one electron dot must put on each side of the element symbol then paired the electrons.

The given molecule is, $ICl_2^-$

As we know that iodine ans chlorine has '7' valence electrons.

Therefore, the total number of valence electrons in $ICl_2^-$ = 7 + 2(7) + 1 = 22

According to Lewis-dot structure, there are 4 number of bonding electrons and 18 number of non-bonding electrons.

Hence, the number of lone pairs of electrons around the central iodine atom are, 6 electrons

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2 years ago

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3 years ago

Combustion analysis is performed on 0.50 g of a hydrocarbon, and 1.47 g of CO2 and 0.902 g of H2O are produced. What is the empi

JulijaS [17]

1. The empirical formula of the hydrocarbon is CH₃

2. The molecular formula of the hydrocarbon is C₂H₆

<h3>How to determine the mass of Carbon </h3>

Mass of CO₂ = 1.47 g
Molar mass of CO₂ = 44 g/mol
Molar of C = 12 g/mol
Mass of C =?

Mass of C = (12 / 44) × 1.47

Mass of C = 0.4 g

<h3>How to determine the mass of H</h3>

Mass of compound = 0.5 g
Mass of C = 0.4 g
Mass of H = ?

Mass of H = (mass of compound) – (mass of C)

Mass of H = 0.5 – 0.4

Mass of H =0.1 g

<h3>1. How to determine the empirical formula </h3>

C = 0.4 g
H = 0.1 g
Empirical formula =?

Divide by their molar mass

C = 0.4 / 12 = 0.03

H = 0.1 / 1 = 0.1

Divide by the smallest

C = 0.03 / 0.03 = 1

H = 0.1 / 0.03 = 3

Thus, the empirical formula of the compound is CH₃

<h3>2. How to determine the molecular formula</h3>

Empirical formula = CH₃
Molar mass = 30 g/mol
Molecular formula =?

Molecular formula = empirical × n = mass number

[CH₃]n = 30

[12 + (3×1)]n = 30

15n = 30

Divide both side by 15

n = 30 / 15

n = 2

Molecular formula = [CH₃]n

Molecular formula = [CH₃]₂

Molecular formula = C₂H₆

Learn more about empirical formula:

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2 years ago

Give the nuclear symbol for the isotope of gallium, ga, that contains 40 neutrons per atom. Replace the question marks with the

Cerrena [4.2K]

The nuclear symbol of an element have three parts namely:

the symbol of an element
mass number of the element
atomic number of the element

The general representation is as:

$_{Z}^{A}X$

where X is the chemical symbol of the element, A is mass number of the element that is total number of neutrons and protons in the nucleus of an atom, and Z is atomic number of the element that is number of protons in the atom.

Element = Gallium, $Ga$ (given)