A face centered cubic cell has an edge length of 495 pm. What is that atomic radius?
1 answer:
Answer:
r = ¼a√2
Explanation:
For a face centered cubic cell, which we call FCC, the atoms at the face diagonals touch each other.
Now, If we denote the edge length of cube to be "a" and the radius of the atom is denoted as "r", as seen in the attached FCC cell:
(√2)a = 4r
Divide both sides by 4 to get;
r = ¼a√2
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Answer:
The volume is
<h2>180 mL</h2>Explanation:
In order to solve for the volume we use the formula for Boyle's law which is
<h3>where
P1 is the initial pressure
V1 is the initial volume
P2 is the final pressure
V2 is the final volume
Since we are finding the final volume we are finding V2
Making V2 the subject we have
<h3>From the question
P1 = 300 mmHg
V1 = 300 mL
P2 = 500 mmHg
Substitute the values into the above formula and solve for the final volume obtained
That's
<h3>We have the final answer as
<h3>180 mL</h3>Hope this helps you