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3 years ago

A face centered cubic cell has an edge length of 495 pm. What is that atomic radius?

Chemistry

1 answer:

Stolb23 [73]3 years ago

5 0

Answer:

r = ¼a√2

Explanation:

For a face centered cubic cell, which we call FCC, the atoms at the face diagonals touch each other.

Now, If we denote the edge length of cube to be "a" and the radius of the atom is denoted as "r", as seen in the attached FCC cell:

(√2)a = 4r

Divide both sides by 4 to get;

r = ¼a√2

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Vlad [161]

C₂H₇ is a covalent compound

N0₄ will be name nitrogen(viii) oxide

MgCl₂ will be named magnesium chloride.

<h3>What are covalent compounds? </h3>

Covalent compounds are compounds which are formed when two electronegative atoms combine together by a sharing of electrons between them.

Covalent compound molecules are usually formed from a combination of non-metals.

The C₂H₇ is a covalent radical formed from the addition of a hydrogen ions to the covalent compound C₂H₆

<h3>What would you name NO₄?</h3>

The name given to a compound depends on the oxidation number of the component elements.

The oxidation number of oxygen is -2.

Since there are 4 atoms of oxygen, the total negative charge is -8.

Nitrogen will have to exist in the +8 state in order to give a neutral compounds.

Therefore, the name given to the compound will be nitrogen (viii) oxide.

<h3>What would you name MgCl₂? </h3>

Magnesium chloride, MgCl₂ is an ionic compound formed from the ionic bond between chlorine and magnesium.

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Learn more about covalent and ionic substances at: brainly.com/question/18660895

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2 years ago

Discribe how continents and oceans are carried on tectonic plates

Vanyuwa [196]

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3 years ago

Which element is most likely to gain an electron?

Oduvanchick [21]

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3 years ago

An insulated container contains 0.3 kg of water at 20 degrees C. An alloy with a mass of 0.090 kg and an initial temperature of

Lorico [155]

Answer:

The specific heat of the alloy is 2.324 J/g°C

Explanation:

<u>Step 1:</u> Data given

Mass of water = 0.3 kg = 300 grams

Temperature of water = 20°C

Mass of alloy = 0.090 kg

Initial temperature of alloy = 55 °C

The final temperature = 25°C

The specific heat of water = 4.184 J/g°C

<u>Step 2:</u> Calculate the specific heat of alloy

Qlost = -Qwater

Qmetal = -Qwater

Q = m*c*ΔT

m(alloy) * c(alloy) * ΔT(alloy) = -m(water)*c(water)*ΔT(water)

⇒ mass of alloy = 90 grams

⇒ c(alloy) = the specific heat of alloy = TO BE DETERMINED

⇒ ΔT(alloy) = The change of temperature = T2 - T1 = 25-55 = -30°C

⇒ mass of water = 300 grams

⇒ c(water) = the specific heat of water = 4.184 J/g°C

⇒ ΔT(water) = The change of temperature = T2 - T1 = 25 - 20 = 5 °C

90 * c(alloy) * -30°C = -300 * 4.184 J/g°C * 5°C

c(alloy) = 2.324 J/g°C

The specific heat of the alloy is 2.324 J/g°C

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3 years ago

Which of the following acids do NOT ionize completely in solution? Check all that apply.

KIM [24]

<span>The following acids do NOT ionize completely in solution because they are not strong acids are as follows:
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c H2SO3
d H3N
e HNO2
f HF
</span>

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3 years ago