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2 years ago

8. What are the next three numbers in this pattern?

Mathematics

2 answers:

Anuta_ua [19.1K]2 years ago

8 0

Answer:

ANSWER =13,24,14 is the answer

Step-by-step explanation:

please follow

dimaraw [331]2 years ago

4 0

13,24,14(D)

Explanation: The

${even}^{th}$

number (i.e 22,23) can be obtained by adding 11 to its previous number. Ex. 23 = 12 + 11

And the odd number(i.e the first, third etc) can be obtained by subtracting 11 from its next number or by adding 1 to the previous odd number(i.e 12 = 11 + 1) Henceforth, the next number will be 12 + 1 = 13

The number after 13 will be 13 + 11 = 24
The number after 24 will be 13 + 1 = 14

<h2>If you found this useful, please mark it as the BRAINLIEST.</h2>

XD

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Hey guys I need some help. Question in the image below

mafiozo [28]

Answer:

15 students at school

Step-by-step explanation:

So there is 50 students in total

First subtract that much with how much students have the flu

1/10 = 5/50

So 5 students have the flu

That leaves 45 students

Then subtract that much with the amount of students that are remaining are on the field trip

45 divided by 3 = 15

so 2/3 = 30/45 (they can both be multiplied and divided by 15)

so 30 of the 45 students are on the field trip

45 - 30 = 15

That means there are 15 students left over at school

5 0

3 years ago

Adam used the three fractions to make

xenn [34]

1/4 because 3 parts of the circle are coloured but 1 part is not and 3+1=4. And that leftover as a fraction is 1/4

5 0

3 years ago

You have $25 to spend on picking 21 pounds of three different types of apples in an orchard. The Empire apples cost $1.40 a

Semmy [17]

Answer:

5 pounds of the Empire apples, 14 pounds of the Red Delicious apples, and 2 pounds of the Golden Delicious apples.

Step-by-step explanation:

Let's call the Empire apples weight at E, the Red Delicious at R, and the Golden Delicious at G. We know that the total weight must be 21 pounds so:

R + E + G = 21 (equation 1)

The total amount of spent must be $25, and the price given is per pound, so the priced paid is the cost multiplied by the weight:

1.40*E + 1.10*R + 1.30*G = 25 (equation 2)

And the weight of the Red Delicious must be equal to twice of the combined weight of the others:

R = 2*(E + G)

E + G = R/2 (equation 3)

Let's substitute equation 3 in equation 1

R + R/2 = 21

(2R + R)/2 = 21

3R = 42

R = 14 pounds.

So, E + G = 7

G = 7 - E (equation 4)

Let's substitute the result of R and the equation 4 in the equation 2:

1.40*E + 1.10*14 + 1.30*(7 - E) = 25

1.40E + 15.40 + 9.10 - 1.30E = 25

0.10E = 25 - 24.50

0.10E = 0.50

E = 5 pounds

G = 7 - E

G = 7 - 5

G = 2 pounds.

3 0

3 years ago

A) 30 : 1, 2, 3, ___,10,15,30 20:1,2,4,- 20 Common Factors:

Archy [21]

Answer:

a)30-1,2,3,5,6,10,15,30

b)20-1,2,4,5,10,20

Step-by-step explanation:

please give me brainlest and follow me

8 0

3 years ago

Read 2 more answers

Will give brainliest, thanks, and 5 stars! LOTS OF POINTS! 50 POINTS!

lubasha [3.4K]

Answer in order:

False

True

False

True

Step-by-step explanation:

All of the solutions to the equation $3x^2 - 12 = 0$ are x = 12 and x = -12

Solve:

Common factor - $3(x^2-4)=0$

Divide both sides

$x^2-4=0$

Use the quadratic formula

$x=\sqrt{4,x}=\sqrt{-4$

x = 2, x = -2

Thus, This is false..

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There are two unique solutions to the equations (x-3)^2 = 16

one variable in matrix = one possible value.

Therefore, x = 7, x = -1

Hence this is True

-------------------------------------------------------------------------------------------------------------

The solutions for the equation 2(x-3)^2-18 = 0 are x = 6 and x = 0

$2x^3-18x^2+54x-72=0$

$x=5.080084$

Hence this is false

-------------------------------------------------------------------------------------------------------------

The solutions for the equation 2(x-5)^2-8=0 are x = 7 and x = -7

Add both sides by 8

2(x-5)^2-8+8=0+8

2(x-5)^2=8

(x-5)^2=4

x = 7, x = 3

Hence, this is false

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The solutions for the equation (x + 3)^2-25 = -8 are x = 2 and x = -8

$(x+3)^2=17$

$x=\sqrt{17-3,}=-\sqrt{17}-3$

Hence this is false.

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The solutions for the equation 2(2x-1)^2=18 are x = 5 and x = -4

$(2x-1)^2=9$

x=2, x = -1

Hence this is false.

-------------------------------------------------------------------------------------------------------------

The only solution for equation (2x-1)^2-49=0 is x = 4

$(2x-1)^2=49$

x = 4, x = -3

Hence, this is false

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The solutions for the equation 3(x+2)^2 - 3 = 0 are x = -3 and x = -1

$3(x+2)^2=3$

$(x+2)^2=1$

x = -1, x = -3

Hence, this is true

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The solutions for the equation 5x^2 - 180 = 0 are x = 6 and x = -6

Add 180 to both sides

$5x^2-180+180=0+180$

$5x^2 = 180$

$x^2 = 36$

$x=\sqrt{36},x=-\sqrt{36}$

x = 6, x = -6

Hence, this is true.

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[RevyBreeze]

7 0

3 years ago